1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
vfiekz [6]
3 years ago
11

Point S is on line segment RT. Given ST = 3x

Mathematics
1 answer:
Strike441 [17]3 years ago
3 0

Answer:

RT = 20

Step-by-step explanation:

Given that,

Point S lies on the line segment RT.

We have, ST = 3x-8, RT = 4x and RS = 4x-7

It is clear that, RT = RS+ST

Putting the values, we get :

4x = 4x-7 + 3x-8

Taking like terms together,

4x-4x-3x = -7-8

-3x = -15

x = 5

Put the value of x in RT = 4x.

So,

RT = 4(5)

RT = 20

Hence, length of RT = 20.

You might be interested in
Which would you use to compare 10 / 12 and 2 / 5 a common numerator or common denominator?
BartSMP [9]

We can compare 2 fractions by means of the cross multiplication method. In our case, we have

since 50 is greater than 24 then 10/12 is greater than 2/5:

\frac{10}{12}>\frac{2}{5}

3 0
1 year ago
4. Andrés desea embaldosar el piso de su casa que tiene 375 cm de ancho y 435 cm de largo. Calcula la longitud del lado que tend
svetlana [45]

Answer:

Sabemos que el piso es un rectángulo de 435 cm de largo y 375 cm de ancho.

Recordar que para un rectángulo de largo L, y ancho W, el área es:

A = L*W

Entonces el área del piso, será:

A = 435cm*375cm = 163,125 cm^2

Primero, sabemos que se utilizaran baldosas (las cuales son cuadradas) y queremos saber la longitud de lado que tendrían las baldosas.

No tenemos ningún criterio para encontrar este lado, solo que (si queremos usar un número entero de baldosas) el largo L del lado de la baldosa deberá ser un divisor de tanto el ancho como el largo del suelo.

Dicho de otra forma

el largo, 435cm, tiene que ser múltiplo de L

el ancho, 375cm, tiene que ser múltiplo de L.

Por ejemplo, ambos números son múltiplos de 5, entonces podríamos tomar L = 5cm

En este caso, el área de cada baldosa es:

a = L^2 = 5cm*5cm = 25cm^2

Y el número total de baldosas que necesitaría usar esta dado por el cociente entre el área del suelo y el area de cada baldosa.

N = ( 163,125 cm^2)/(25cm^2) = 6,525 baldosas.

También sabemos que ambos números (435cm y 375cm) son múltiplos de 15cm

Entonces las baldosas podrían tener 15cm de lado.

En este caso, el área de cada baldosa es:

A = (15cm)^2 = 225cm

En este caso el número total de baldosas necesarias será:

N =  ( 163,125 cm^2)/(225cm^2) = 725 baldosas.

5 0
3 years ago
NEED HELP PLEASE as soon as possible!!!
dolphi86 [110]

Answer:

b 0.33333333333333333

8 0
4 years ago
Please help
Vinil7 [7]

Answer:

$3,075

Step-by-step explanation:

Given, for a triangular sail (assuming its a right triangle)

base dimension = 15 feet

height = 20 feet

Area of sail,

= area of right triangle

= 1/2 x base x height

= 1/2 x 15 x 20

= 150 ft²

we are given that the price per squre foot is $20.50

hence cost of sail

= price per square foot x area of sail

= $20.50 x 150 ft²

= $3,075

6 0
3 years ago
In Jeopardy, if you answer a question
Nata [24]
-150 points cause 200-350= -150
7 0
3 years ago
Other questions:
  • How do you show work for this question?
    10·1 answer
  • Suppose the average yearly salary of an individual whose final degree is a​ master's is ​$ thousand less than twice that of an i
    13·1 answer
  • S=2B+F. Solve for B (With steps)
    8·1 answer
  • Round 462 to the nearest 100.
    5·2 answers
  • PLS PLS HELP! WILL GIVE BRAINLIEST IF ALL QUESTIONS ARE ANSWERED AND IF THEY’RE RIGHT!
    15·1 answer
  • If you've lived 409968000 hours, how old are you?
    8·1 answer
  • Could anyone help me with this question? Thank you!
    8·1 answer
  • List the values of this inequality
    8·1 answer
  • Can someone help me with this
    9·1 answer
  • On Tuesday, the baker makes 60 total cupcakes. How many chocolate cupcakes does the baker make on Tuesday?
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!