Given:
The equation of circle is
To find:
The polar form of given circle.
Solution:
We have,
![[\because (a+b)^2=a^2+2ab+b^2]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%28a%2Bb%29%5E2%3Da%5E2%2B2ab%2Bb%5E2%5D)
Subtracting 9 from both sides, we get
We know that, 
and 
.
and 
We know that, r is radius it cannot be 0. So,
Therefore, the correct option is A.
3+3+3+3 is the answe because there are 4 rows of three
Answer:
a = 14
Step-by-step explanation:
<u>Step 1: Write out your problem</u>
f (a) = 5a + 14 | f (a) = 0
<u>Step 2: Solve</u>
f (a) = 5 (0) + 14 , Input a.
f (a) = 0 + 14 , 5 x 0 = 0
(a) = 14 , 0 + 14
a = 14
Answer:
A. √16
Step-by-step explanation:
A perfect square is any number that can be expressed as a product of an integer and itself. i.e. 4 can be represented as 2 × 2. Therefore, 4 is a perfect square.
From the options given, the only radical expression that has two perfect square is √16.
√16 consists of two perfect squares, which are 4 and 4.
4 can be expressed as 2 × 2.
Thus: √16 = √(2 × 2)(2 × 2).
Therefore, √16 consists of two perfect squares.
It is already in simplest form, since 17 is a prime number.
