solution: Mr. Schwartz will need to order more wheels after building 12 cars.
explanation:
Mr. Schwartz begins with total number of wheels = 85
he has to order more wheels once he left with less than 40 wheels
so min. no. of wheels he can use before ordering more wheels = 85-40 = 45
Mr. Schwartz uses 4 wheels to build 1 car
Mr. Schwartz uses 45 wheels to build 45÷4 = 11.25 cars
then, if he builds 12 cars then he needs 12×4 = 48 wheels
total supply of wheels he begins with = 85
wheels he used to build 12 cars = 48
so total number of wheels remaining are = 85-48 = 37
since 37 is less than 40 so after building 12 cars Mr. Schwartz need to order more wheels.
Answer:
V≈8.44×10-6m³
r Radius
mm
h Height
mm
Unit Conversion:
r=8×10-3m
h=0.042m
Solution
V=πr2h=π·8×10-32·0.042≈8.4446×10-6m³
Step-by-step explanation:
Answer:
b
Step-by-step explanation:
