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3 years ago

A 9-pack of notebooks costs $3.87. What is the unit price?

Mathematics

2 answers:

wel3 years ago

5 0

Answer:

$0.43

Step-by-step explanation:

First, we must divide $3.87 by 9.

$3.87 \div 9 = 0.43$

Hope this helped :)

Please mark brainliest if it helped.

Nonamiya [84]3 years ago

4 0

Answer:

3.87 in total / 9 notebooks = 0.43 dollars per pack

To find the unit price just divide

Hope this helps

Step-by-step explanation:

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Goshia [24]

Answer:

Stephanie brought the 20 chocolate for $50

Step-by-step explanation:

If she have $60 and only have $10 left that would me that the chocolate are $50

5 0

3 years ago

A line is an undefined term because it

Svet_ta [14]

Answer:

Option C) describes something that does not have width or depth

Step-by-step explanation:

We are given the following information in the question:

We may define line as:

A line is a straight one-dimensional figure having no thickness and extending infinitely in both directions.
A line is sometimes called a straight line.
It is demonstrated by arrow on both sides showing that it can be extended on both sides.
A line can be considered undefined term because it tells us about something that does not have width or depth.
A lines can extend its length in both side infinitely. It contains arrowheads indicating it can extend.

Thus, the correct option is Option C) describes something that does not have width or depth.

8 0

3 years ago

Read 2 more answers

How can i prove this property to be true for all values of n, using mathematical induction.

chubhunter [2.5K]

Proof -

So, in the first part we'll verify by taking n = 1.

$\implies \: 1 = {1}^{2} = \frac{1(1 + 1)(2 + 1)}{6}$

$\implies{ \frac{1(2)(3)}{6} }$

$\implies{ 1}$

Therefore, it is true for the first part.

In the second part we will assume that,

$\: { {1}^{2} + {2}^{2} + {3}^{2} + ..... + {k}^{2} = \frac{k(k + 1)(2k + 1)}{6} }$

and we will prove that,

$\sf{ \: { {1}^{2} + {2}^{2} + {3}^{2} + ..... + {k}^{2} + (k + 1)^{2} = \frac{(k + 1)(k + 1 + 1) \{2(k + 1) + 1\}}{6}}}$

$\: {{1}^{2} + {2}^{2} + {3}^{2} + ..... + {k}^{2} + (k + 1)^{2} = \frac{(k + 1)(k + 2) (2k + 3)}{6}}$

${1}^{2} + {2}^{2} + {3}^{2} + ..... + {k}^{2} + (k + 1)^{2} = \frac{k (k + 1) (2k + 1) }{6} + \frac{(k + 1) ^{2} }{6}$

${1}^{2} + {2}^{2} + {3}^{2} + ..... + {k}^{2} + (k + 1)^{2} = \frac{k(k+1)(2k+1)+6(k+1)^ 2 }{6}$

${1}^{2} + {2}^{2} + {3}^{2} + ..... + {k}^{2} + (k + 1)^{2} = \frac{(k+1)\{k(2k+1)+6(k+1)\} }{6}$

${1}^{2} + {2}^{2} + {3}^{2} + ..... + {k}^{2} + (k + 1)^{2} = \frac{(k+1)(2k^2 +k+6k+6) }{6}$

${1}^{2} + {2}^{2} + {3}^{2} + ..... + {k}^{2} + (k + 1)^{2} = \frac{(k+1)(2k^2+7k+6) }{6}$

${1}^{2} + {2}^{2} + {3}^{2} + ..... + {k}^{2} + (k + 1)^{2} = \frac{(k+1)(k+2)(2k+3) }{6}$

Henceforth, by using the principle of mathematical induction 1²+2² +3²+....+n² = n(n+1)(2n+1)/ 6 for all positive integers n.

_______________________________

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8 0

2 years ago

I need help it is due today

faltersainse [42]

The reason why the trails must be in quadrant 2 or 3 is because the coordinates start with a negative number. Quadrant 2= (-,+) and quadrant 3= (-,-)

8 0

2 years ago

Which ordered pair is on the graph of the function? O (-1,2) O (6,-3) O (-2,-4) O (-6, 4)

tino4ka555 [31]

Answer:

(6, -3)

Step-by-step explanation:

7 0

3 years ago