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vodka [1.7K]
3 years ago
11

Which translation moves the entire figure into Quadrant II?

Mathematics
2 answers:
Svet_ta [14]3 years ago
8 0

Answer:

bean

Step-by-step explanation:

Novay_Z [31]3 years ago
7 0
Bean vhyjcxsfhnkj cfhjkko
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How many different ways are there to choose a dozen donuts from the 4 varities at a donut shop so that you get atleast one donut
Leno4ka [110]

There are 330 different ways for choosing a dozen donuts from the 4 varieties at a donut shop. (at least one donut of every variety must be selected)

<h3>How to calculate the number of ways to select items?</h3>

There are 'r' items from 'n' different varieties (repetition allowed). Then, the number of ways to select items is given by

The number of ways =  _{n+r-1}C_r

Where the combination _{n}C_r is calculated as

_{n}C_r=\frac{n!}{r!(n-r)!}

<h3 /><h3>Calculation:</h3>

It is given that there are 4 varieties of donuts in a shop. I.e., n = 4

Number of donuts to be selected r = 12 (one dozen)

And also given that at least one donut of every variety has to be selected.

Since there are 4 varieties, at least one from each of these means the count is 4.

So, the remaining number of donuts to be selected is 12 - 4 = 8.

So, r becomes 8 i.e., r = 8

On substituting,

the number of ways of selecting the remaining 8 donuts = _{4+8-1}C_4

⇒ _{11}C_4

⇒ \frac{11!}{4!(11-4)!}

⇒ \frac{11!}{(4!)(7!)}

⇒ 330

Therefore, there are 330 different ways for choosing a dozen donuts from the 4 varieties at a donut shop.

Learn more about combinations here:

brainly.com/question/11732255

#SPJ4

5 0
2 years ago
The admission fee at an amusement park is $6.50 for children and $15.00 for adults. On a certain day, 337 people entered the par
DerKrebs [107]

Answer:

192 children and 145 adults were admitted.

Step-by-step explanation:

Let c represent the amount of children and let a represent the amount of adults.

Total fees for children = (Fee for one child) x (Amount of children) = 6.5c

Total fees for adults = (Fee for one adult) x (Amount of adults) = 15a

Total fees = Total fees for children + Total fees for adults

3423 = 6.5c +15a

We know that the amount of people who entered the park was 337. Therefore a+c=337, which means a=337-c.

Sub this in to the equation above to get:

3423 = 6.5c +15 (337-c)

3423 = 6.5c + 5055 - 15c

-1632 = -8.5c

c = 192

So there were 192 children.

Since a=337-c and c=192, a=337-192=145. So there were 145 adults.

5 0
3 years ago
the brightness of the illumination of an object varies inversely as the square of the distance from the object to the source of
Andre45 [30]
I=k/d^2

4=k/d^2 and 1=k/64  so if we divide the first by the second we get:

4/1=(k/d^2)/(k/64)

4=(k/d^2)*(64/k)

4=64/d^2

d^2=64/4

d^2=16

d=4 meters


5 0
3 years ago
describe how you might pick a sample of 50 minivan owners that represent the minivan owners of your state
MrRa [10]
You can advertise that you need a sample of 50 minivan owners, and use them as a representative of the state. But this is biased and has some inaccuracy.
3 0
4 years ago
Please Solve:
Ludmilka [50]
16 as 1-4 =4secs so 1-16=16
7 0
4 years ago
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