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lesya692 [45]
3 years ago
6

PLEASE HELP ASAP!!!

Mathematics
1 answer:
EleoNora [17]3 years ago
5 0
<span>Part 1:

(x+1)^2-3(x+2) \\  \\ =x^2+2x+1-3x-6 \\  \\ =x^2-x-5

option b.


Part 2:
(5x^3y^{-3})(-6x^4y)\\ \\=5(-6)x^{3+4}y^{-3+1}\\ \\=-30x^7y^{-2}\\ \\=\frac{-30x^7}{y^2}

option d


Part 3:
\frac{8+x}{2} - \frac{x+3}{3} =4

Multiply through by the LCM of 2 and 3 (i.e. 6)
6\left(\frac{8+x}{2}\right) - 6\left(\frac{x+3}{3}\right) =6(4) \\  \\ 3(8+x)-2(x+3)=24 \\  \\ 24+3x-2x-6=24 \\  \\ x+18=24 \\  \\ x=24-18=6

option b


Part 4
x^2-3x-8=x+4

x^2-3x-8=x+4 \\  \\ x^2-3x-x-8-4=0 \\  \\ x^2-4x-12=0 \\  \\ (x-6)(x+2)=0 \\  \\ x=6 \ or \ -2

option d


Part 5
Joseph is solving the equation x^2+8x-4=0 using the technique completing the square.
x^2+8x-4=0
x^2+8x+?=4+?

In completeing the square method, you divide the coeficient of x by 2, square the result and add to both sides of the equation.

Therefore, he should add 16 to both sides because (8/2)^2=16.

option d.
</span>
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Find the cotangent of angle B. <br> 1. 12/5<br> 2. 12/13<br> 3. 13/12<br> 4. 5/12
labwork [276]
Cot = Cos/Sin

Cos = 12/13
Sin = 5/13

Therefore, 12/3 divided by 5/13 equals 12/5

Answer is 1.

3 0
3 years ago
Read 2 more answers
Please help ASAP!!!!!
Viefleur [7K]
Use pythagorean’s theorem
as you can see it’s a right isosceles triangle

so your equation is adapted to this:
p^2 + p^2=44^2
add like terms and simplify
2p^2=1936
divide by 2
p^2=968
square root
p= √968
simplify
p=22√2

the answer would be your second option
3 0
3 years ago
Hep asappppppppppppp
schepotkina [342]

Answer:

(6 , -1)

Step-by-step explanation:

2x+  y  = 11   ----------------(I)

y = 11 - 2x --------------------(II)

\frac{1}{2}x - 5y = 8

Multiply the whole equation by 2

2*\frac{1}{2}x -2*5y = 2*8

x - 10y = 16 --------------------(III)

Substitute y = 11- 2x in equation (III)

x - 10(11 - 2x) = 16

x - 110 + 20x = 16

21x - 110 = 16

21x = 16 +110

21x = 126

x = 126/21

x = 6

Plugin x = 6 in equation (II)

y = 11 - 2*6

y = 11 - 12

y = -1

5 0
2 years ago
Hi, can someone please help, and possibly explain the answer please.
mr_godi [17]

Answer:

x=\frac{-(-2)\±\sqrt{(-2)^2-4(3)(0)} }{2(3)}

Step-by-step explanation:

Quadratic formula: x=\frac{-b\±\sqrt{b^2-4ac} }{2a} when the equation is 0=ax^2+bx+c

The given equation is 1=-2x+3x^2+1. Let's first arrange this so its format looks like y=ax^2+bx+c:

1=-2x+3x^2+1

1=3x^2-2x+1

Subtract 1 from both sides of the equation

1-1=3x^2-2x+1-1\\0=3x^2-2x+0

Now, we can easily identify 3 as a, -2 as b and 0 as c. Plug these into the quadratic formula:

x=\frac{-b\±\sqrt{b^2-4ac} }{2a}\\x=\frac{-(-2)\±\sqrt{(-2)^2-4(3)(0)} }{2(3)}

I hope this helps!  

8 0
3 years ago
What is the simplified form of
umka21 [38]

<em>Note: Your answer choices remain a little unclear. But, I have solved the concept and solution, so you can easily figure it out.</em>

Answer:

\left(-7x^0+5x^2-x+6\right)-\left(-8x^2+x+3\right)=13x^2-2x-4

Step-by-step explanation:

Given the expression

\left(-7x^0+5x^2-x+6\right)-\left(-8x^2+x+3\right)

solving the expression

=-7x^0+5x^2-x+6-\left(-8x^2+x+3\right)

apply the rule: a^0=1,\:a\ne \:0

=-7+5x^2-x+6-\left(-8x^2+x+3\right)

=-7+5x^2-x+6+8x^2-x-3

simplify

=13x^2-2x-4

Therefore, the simplified form is:

\left(-7x^0+5x^2-x+6\right)-\left(-8x^2+x+3\right)=13x^2-2x-4

<em>Note: Your answer choices remain a little unclear. But, I have solved the concept and solution, so you can easily figure it out.</em>

8 0
3 years ago
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