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defon
3 years ago
8

A number that is a whole number but not an integer?

Mathematics
1 answer:
Burka [1]3 years ago
4 0

Answer:

-5 is the answer

Hope it will be helpfull....

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Help, I don’t understand
Sedbober [7]

Answer:

A=90°,B=90°,C=90°,D=90°

Step-by-step explanation:

all of the numbers A-D add up to 360°

6 0
3 years ago
The perimeter of a pentagon (5 sides) is 10.5 centimeters. The sides are x,x,x,x and 1.7 cm. What is the value of x
Drupady [299]

Answer:

What did she sayyyyyyyy? Um I don't know what x,x,x,x is ma'am or sir

Step-by-step explanation:

4 0
3 years ago
Which of the following is the equation of a circle with a radius of 10 cm and center at (–3, 6)?
Volgvan

The equation of the circle:

(x-h)^2+(y-k)^2=r^2

(h, k) - center

r - radius

We have:

r=10\\(-3,\ 6)\to h=-3,\ k=6

Substitute:

(x-(-3))^2+(y-6)^2=10^2\\\\(x+3)^2+(y-6)^2=100

4 0
3 years ago
You roll fair6-sided die what is P(roll a 2)?
creativ13 [48]

Answer:

1/6

Step-by-step explanation:

It is a 6 sided die, so you have 6 possibilities, so that is going to be you denominator.

There is only one number 2 on the die, so you have 1 as your numerator.

5 0
3 years ago
Read 2 more answers
given the recursive formula for a geometric sequence find the common ratio the 8th term and the explicit formula.did I set these
lesya [120]

Answer:


Step-by-step explanation:

1)Since we know that recursive formula of the geometric sequence is

a_{n}=a_{n-1}*r

so comparing it with the given recursive formula a_{n}=a_{n-1}*-4

we get common ratio =-4

8th term= a_{1}*(r)^{n-1}=-2*(-4)^{7} =32768.

Explicit Formula =-2*(-4)^{n-1}

2) Comparing the given recursive formula a_{n}=a_{n-1}*-2

with standard recursive formula a_{n}=a_{n-1}*r

we get common ratio =-2

8th term= a_{1}*(r)^{n-1}=-4*(-2)^{7} =512.

Explicit Formula =-4*(-2)^{n-1}

3)Comparing the given recursive formula a_{n}=a_{n-1}*3

with standard recursive formula a_{n}=a_{n-1}*r

we get common ratio =3

8th term= a_{1}*(r)^{n-1}=-1*(3)^{7} =-2187.

Explicit Formula =-1*(3)^{n-1}

4)Comparing the given recursive formula a_{n}=a_{n-1}*-4

with standard recursive formula a_{n}=a_{n-1}*r

we get common ratio =-4

8th term= a_{1}*(r)^{n-1}=3*(-4)^{7} =-49152.

Explicit Formula =3*(-4)^{n-1}

5)Comparing the given recursive formula a_{n}=a_{n-1}*-4

with standard recursive formula a_{n}=a_{n-1}*r

we get common ratio =-4

8th term= a_{1}*(r)^{n-1}=-4*(-4)^{7} =65536.

Explicit Formula =-4*(-4)^{n-1}

6)Comparing the given recursive formula a_{n}=a_{n-1}*-2

with standard recursive formula a_{n}=a_{n-1}*r

we get common ratio =-2

8th term= a_{1}*(r)^{n-1}=3*(-2)^{7} =-384.

Explicit Formula =3*(-2)^{n-1}

7)Comparing the given recursive formula a_{n}=a_{n-1}*-5

with standard recursive formula a_{n}=a_{n-1}*r

we get common ratio =-5

8th term= a_{1}*(r)^{n-1}=4*(-5)^{7} =-312500.

Explicit Formula =4*(-5)^{n-1}

8)Comparing the given recursive formula a_{n}=a_{n-1}*-5

with standard recursive formula a_{n}=a_{n-1}*r

we get common ratio =-5

8th term= a_{1}*(r)^{n-1}=2*(-5)^{7} =-156250.

Explicit Formula =2*(-5)^{n-1}

6 0
3 years ago
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