Answer:
- A'(4, -4)
- B'(0, -3)
- C'(2, -1)
- D'(3, -2)
Step-by-step explanation:
The coordinate transformation for a 270° clockwise rotation is the same as for a 90° counterclockwise rotation:
(x, y) ⇒ (-y, x)
The rotated points are ...
A(-4, -4) ⇒ A'(4, -4)
B(-3, 0) ⇒ B'(0, -3)
C(-1, -2) ⇒ C'(2, -1)
D(-2, -3) ⇒ D'(3, -2)
_____
<em>Additional comment</em>
To derive and/or remember these transformations, it might be useful to consider where a point came from when it ends up on the x- or y-axis.
A point must have come from the -y axis if rotating it 270° CW makes it end up on the +x-axis. A point must have come from the x-axis if rotating it 270° makes it end up on the +y axis. That is why we write ...
(x, y) ⇒ (-y, x) . . . . . . the new x came from -y; the new y came from x
Answer:
28
Step-by-step explanation:
x=12 and y=3
x=4 and y =1
x=28 and y=7
-5+6 = 1. This is the answer. Thank you
Answer:
84
Step-by-step explanation:
<em>i dont know if this is right or not but basscially you do 60 divided by 5/7 and yea....</em>
Answer:
Step-by-step explanation:
We have been given an equation 
. We are asked to find the zeros of equation by factoring and then find the line of symmetry of the parabola.
Let us factor our given equation as:
Dividing both sides by 2:
Splitting the middle term:
Using zero product property:
Therefore, the zeros of the given equation are .
We know that the line of symmetry of a parabola is equal to the x-coordinate of vertex of parabola.
We also know that x-coordinate of vertex of parabola is equal to the average of zeros. So x-coordinate of vertex of parabola would be:
Therefore, the equation represents the line of symmetry of the given parabola.
