Answer:
![\displaystyle Range: Set-Builder\:Notation → [y|-2 ≤ y] \\ Interval\:Notation → [-2, ∞) \\ \\ Domain: Set-Builder\:Notation → [x|-4 ≤ x] \\ Interval\:Notation → [-4, ∞)](https://tex.z-dn.net/?f=%5Cdisplaystyle%20Range%3A%20Set-Builder%5C%3ANotation%20%E2%86%92%20%5By%7C-2%20%E2%89%A4%20y%5D%20%5C%5C%20Interval%5C%3ANotation%20%E2%86%92%20%5B-2%2C%20%E2%88%9E%29%20%5C%5C%20%5C%5C%20Domain%3A%20Set-Builder%5C%3ANotation%20%E2%86%92%20%5Bx%7C-4%20%E2%89%A4%20x%5D%20%5C%5C%20Interval%5C%3ANotation%20%E2%86%92%20%5B-4%2C%20%E2%88%9E%29)
Explanation:
<em>See above graph</em>
I am joyous to assist you anytime.
The values that make this statement falser are any in which a and b do not have the same sign.
For instance, if a was equal to 3 and b was equal to -3 than see the results.
|a+b|=
|3+-3|=
|0|= 0
Then see the next equation with the same selections
|a|+|b|
|3|+|-3|
3 + 3 = 6
And this would be true no matter which is the negative, as long as there is one negative and one positive.
What grade is this? I can get the answer of it but I forgot how
