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navik [9.2K]
3 years ago
8

1

Mathematics
1 answer:
earnstyle [38]3 years ago
3 0
Hey there! :D

1. 7.6 repeating ____ 55 squared 

Find 55 squared. 

7.6 < 3025

7.6 is less than 7.4. 

2. We already know we have 11 as the whole number. 

When you have a repeating decimal, you can keep it as a fraction but use 99 as the denominator. 

42/99 with the 11 whole number is the answer.

3. -31/6, -5, -5/6, -26^2 <== least to greatest. 

-31/6= -5.16667 -26^2= 676

4. I think the 50 is the square root. Everything else can be represented as a fraction or ratio. The square root of 50 is irrational, and cannot be represented by a fraction or ratio. 50 squared is the one that doesn't belong.

I hope this helps!
~kaikers
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Uzanne can work 10 math problems in 15 minutes. How many can she work in an hour and a half?
jeyben [28]
1 and half hour
= 60 minutes+ 30 minutes
= 90 minutes

Now,

Uzanne need 15 minutes to do 10 problems
Uzanne need 1 minute to complete 10/15 problems

Uzanne need 90 minutes to do
= (10/15)*90
=(2/3)*90
=2*30
=60 problems
4 0
3 years ago
A yellow ball, a red ball, a white ball and a
OleMash [197]

Answer:

1/4 chance (this is equal to 25% as a percentage or 0.25 as a decimal)

Step-by-step explanation:

There are 4 balls and only one can be first. As there is only 1 yellow ball, there is 1/4 chance that the yellow ball is picked first.

4 0
3 years ago
Describe a scenario where the function value exists at x=c, but the limit does not exist.
Vikki [24]

The scenario can be described using a piecewise function like:

f(x) = 1/x                  if  x < c.

f(x) = x                    if   x = c

f(x) = 1/(x + 73)       if x > c.

<h3>When the value exists but the limit does not?</h3>

Remember that the limit only exists if the limit from left and the limit from the right give the same value.

Then, we can just define a piecewise function of the form:

f(x) = 1/x                  if  x < c.

f(x) = x                    if   x = c

f(x) = 1/(x + 73)       if x > c.

Clearly, this is not a continuous function.

Notice that:

f(c) = c.\\\\ \lim_{x \to c^{-}} f(x) = 1/c\\\\ \lim_{x \to c^{+}} f(x) = 1/(c + 73)

So the limits from left and right are different, then:

\lim_{x \to c^{}} f(x)

Does not exist.

If you want to learn more about limits:

brainly.com/question/5313449

#SPJ1

6 0
2 years ago
Simplify the expression. 2a^-5 m^5
Komok [63]
2a^-5= 1/2a^5
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3 years ago
Use substitution to solve the system of equations. How many solutions are there? 1/2x − 1/3y = 5 x = 2/3y + 10
Vadim26 [7]

Answer:

2 solutions cuz

2 variable are there

7 0
3 years ago
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