Quadratic equation whose roots are 6 and 4, and whose leading coefficient is 5 .

Is 7x=5x-25+30 no solution,one solution, or all real numbers? Thank you!

viva [34]

One solution let's find that

$\\ \rm\hookrightarrow 7x=5x-25+30$

$\\ \rm\hookrightarrow 7x=5x+5$

$\\ \rm\hookrightarrow 2x=5$

$\\ \rm\hookrightarrow x=5/2$

6 0

2 years ago

7p-(3p+4) = -2(2p-1)+10 Please answer!!!!!!!

Zanzabum

P=2
Work:
7p−(3p+4)=−2(2p−1)+107p−(3p+4)=−2(2p−1)+107p+−1(3p+4)=−2(2p−1)+107p+−1(3p)+(−1)(4)=−2(2p−1)+107p+−3p+−4=−2(2p−1)+107p+−3p+−4=(−2)(2p)+(−2)(−1)+107p+−3p+−4=−4p+2+10(7p+−3p)+(−4)=(−4p)+(2+10)4p+−4=−4p+124p−4=−4p+124p−4+4p=−4p+12+4p8p−4=128p−4+4=12+48p=168p8‌=‌168‌p=2

Hope this helps:)

8 0

3 years ago

Read 2 more answers

Solve for w. 4 = 0.25(w-4.3)

Snezhnost [94]

W=20.3

solve what's in the parenthesis, move the terms, calculate, then divide both sides.

8 0

3 years ago

Rename the fraction 1/4 using the least common denominator,12

kiruha [24]

Answer:

3/12

Step-by-step explanation:
to rename the fraction with the common denominator of 12, u have to multiply 1/4 by 3/3 to get 3/12. You can check ur answer by simplifying your answer. 3/12=1/4

4 0

1 year ago

Read 2 more answers

A 20ft ladder is leaning against a house. The bottom of the ladder is 3 ft from the house. To the nearest tenth of a foot, abou

Tasya [4]

Answer: 19.8 ft

Step-by-step explanation:

Use the Pythagorean Theorem formula to solve for how high the top of the ladder reach.

The formula says a^2 + b^2 = c^2

Where a and b are the two legs and C is the hypotenuse.

In this situation, the hypotenuse will be length of the ladder , and either a or b will be the length of the ladder from the building or the length of how long the ladder.

a will be 3 , and c will be 20. Input in the values into the formula and solve for b.

3^2 + b^2 = 20^2

9 + b^2 = 400

-9 -9

b^2 = 391

b = $\sqrt{391}$

b = 19.77371 round to the nearest tenth is , 19.8

8 0

2 years ago