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LenKa [72]
3 years ago
11

Quadratic equation whose roots are 6 and 4, and whose leading coefficient is 5 .

Mathematics
1 answer:
Gwar [14]3 years ago
3 0

Answer:

f(x)= 5x^(2)-10x-120

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3x - 2y = 10
natka813 [3]
3x - 2y = 10
10x + 2y = 8 (everything *2)
minus
Therefore final equation is -7x = 2 B
3 0
3 years ago
Sam and Mary collect marbles. “If you give me 5 marbles I’ll have twice as many as you.” said Sam to Mary.
ivann1987 [24]

Answer:

54 marbles

Step-by-step explanation:

The question is a word problem leading to a simultaneous equation

Let 'x' represent the initial number of marbles with Sam, and let 'y' represent the initial number of marbles with Mary,

If Mary gives Sam 5 marbles, we have;

x + 5 = 2 × (y - 5)...(1)

If Sam gives Mary 4 marbles, we get;

x - 4 = y + 4...(2)

From equation (1), we get;

x + 5 = 2 × (y - 5) = 2·y - 10

x = 2·y - 10 - 5 = 2·y - 15

x = 2·y - 15...(3)

From equation (2), we have;

x - 4 = y + 4

∴ x = y + 4 + 4 = y + 8

x = y + 8...(4)

Equating the two values of 'x' in equation (3), and equation (4), we get;

2·y - 15 = y + 8

2·y - y = 8 + 15 = 23

∴ y = 23

From equation (4), we get;

x = y + 8 = 23 + 8 = 31

x = 31

The total number of marbles they have altogether = x + y

However, x + y = 23 + 31 = 54

Therefore;

The total number of marbles they have altogether = 54 marbles.

7 0
3 years ago
Jessie wrote a computer program to create colored shapes. The shapes are either squares or circular and both are equally likely.
GenaCL600 [577]
Hey! The answer is "<span>B)16 2/3%." Hope I helped, and have a great day!

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3 0
3 years ago
Read 2 more answers
I need to find the derivative. I’m not very good at this so I am answer asap would be sosososo helpful
Bingel [31]

Answer:

See below.

Step-by-step explanation:

First, notice that this is a composition of functions. For instance, let's let f(x)=\sqrt{x} and g(x)=7x^2+4x+1. Then, the given equation is essentially f(g(x))=\sqrt{7x^2+4x+1}. Thus, we can use the chain rule.

Recall the chain rule: \frac{d}{dx}[f(g(x))]=f'(g(x))\cdot g'(x). So, let's find the derivative of each function:

f(x)=\sqrt{x}=x^\frac{1}{2}

We can use the Power Rule here:

f'(x)=(x^\frac{1}{2})'=\frac{1}{2}(x^{-\frac{1}{2}  })=\frac{1}{2\sqrt{x}}

Now:

g(x)=7x^2+4x+1

Again, use the Power Rule and Sum Rule

g'(x)=(7x^2+4x+1)'=(7x^2)'+(4x)'+(1)'=14x+4

Now, we can put them together:

y'=f'(g(x))\cdot g'(x)=\frac{1}{2\sqrt{g(x)}} \cdot (14x+4)

y'=\frac{14x+4}{2\sqrt{7x^2+4x+1} } =\frac{7x+2}{\sqrt{7x^2+4x+1} }

5 0
3 years ago
If you help me and explain how you got your answer you will get brainlisyt
Oksanka [162]

Answer:

36.72

Step-by-step explanation:

Take 60% of 61.20. That is the markup.

60% * 61.20 = 60/100 * 61.2 = 3672/100 = 36.72

The markup is 36.72

8 0
2 years ago
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