Question

In ΔQRS, the measure of ∠S=90°, RS = 2.2 feet, and QR = 4.5 feet. Find the measure of ∠Q to the nearest tenth of a degree.

Answer 1

Answer:

$Q = 29.3^\circ$

Step-by-step explanation:

Given

$\angle S = 90$

$RS = 2.2ft$

$QR = 4.5ft$

See attachment for ΔQRS

To calculate <Q, we make use of:

$sin\ Q = \frac{Opposite}{Hypotenuse}$

Where

$Opposite = RS$

$Hypotenuse = QR$

$sin\ Q = \frac{RS}{QR}$

$sin\ Q = \frac{2.2}{4.5}$

$sin\ Q = 0.4889$

Take arc sin of both side

$Q = sin^{-1}(0.4889)$

$Q = 29.3^\circ$