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nadezda [96]
3 years ago
5

Two planes start from the same airport and fly in opposite directions. the second plane starts 1/2 hour after the first plane, b

ut its speek is 50 miles per hour faster. find the air speed of cach plan, if 2 hours after the first plante departs, the plans are 2000 miles apart
Mathematics
1 answer:
Lina20 [59]3 years ago
8 0
First plane
t = 2 hours.
r = r

Second plane
t = 1.5 hours
(30 minutes = 1/2 hour. the second plain has been in the air 2 - 1/2 hour = 1.5 hours. )
r = r + 30

Equation
2 * r + 1.5(r  + 50) = 2000
2r + 1.5r + 75 = 2000
3.5r = 2000 - 75
3.5r = 1925 
r = 1925 / 3.5
r = 550

the first plane was going 550 mph
the second plan was going 600 mph
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5.7 years

Step-by-step explanation:

we know that    

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in this problem we have  

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substitute in the formula above

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\frac{11.8}{9} =(1.011875)^{4t}  

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Applying log both sides

log(\frac{11.8}{9})=log[(1.011875^{4})^{t}]  

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4 0
3 years ago
Help please, I'm stuck on this :/
nlexa [21]

Do you have a calculator? you can solve it by substituting x.

y=16x^2

0: y = 16(0)^2 = 16(0) = 0

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0.5: y = 16(0.5)^2 = 16(0.25) = 4

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I'm not sure about the pattern, but if you graph it, it'll be symmetrical across the y-axis.

8 0
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