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nadezda [96]
3 years ago
5

Two planes start from the same airport and fly in opposite directions. the second plane starts 1/2 hour after the first plane, b

ut its speek is 50 miles per hour faster. find the air speed of cach plan, if 2 hours after the first plante departs, the plans are 2000 miles apart
Mathematics
1 answer:
Lina20 [59]3 years ago
8 0
First plane
t = 2 hours.
r = r

Second plane
t = 1.5 hours
(30 minutes = 1/2 hour. the second plain has been in the air 2 - 1/2 hour = 1.5 hours. )
r = r + 30

Equation
2 * r + 1.5(r  + 50) = 2000
2r + 1.5r + 75 = 2000
3.5r = 2000 - 75
3.5r = 1925 
r = 1925 / 3.5
r = 550

the first plane was going 550 mph
the second plan was going 600 mph
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Step-by-step explanation:

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\frac{dP}{dt}=kP(1-P)\\\\ \int \frac{dP}{P-P^2} =k\int dt\\\\-ln(1-\frac{1}{P})+C_1=kt\\\\1-\frac{1}{P}=Ce^{-kt}\\\\\frac{1}{P}=1-Ce^{-kt}\\\\P=\frac{1}{1-Ce^{-kt}}

P(0)=  \frac{1}{1-Ce^{-kt}}=\frac{1}{1-C}=100\\\\1-C=0.01\\\\C=0.99\\\\\\P(3)=  \frac{1}{1-0.99e^{-3k}}=300\\\\1-0.99e^{-3k}=\frac{1}{300}=0.99e^{-3k}=1-1/300=0.997\\\\e^{-3k}=0.997/0.99=1.007\\\\-3k=ln(1.007)=0.007\\\\k=-0.007/3=-0.00224=-1/447

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