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Dmitrij [34]
3 years ago
12

A bird watcher is standing 50 feet from the base of a large tree. The surveyor measures the angle of elevation to a bird on top

of the tree as 71.5. How y'all is the tree?
Mathematics
1 answer:
yan [13]3 years ago
5 0

Answer:

149.43 feet tall

Step-by-step explanation:

From the base of a large tree, a bird watcher is standing 50 feet away.

There is 71.5° of elevation from the bird watcher to a bird on the top of the tree.

If we ignore the height of the observer and consider the height of the tree as h feet, then using trigonometry we can write that

tan 71.5° = \frac{h}{Base} = \frac{h}{50}

Hence, h = 50 tan 71.5° =149.43 feet.

Therefore, the tree is 149.43 feet tall. (Answer)

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In what form is the following linear equation written? y-3=2/3(x-1)
lions [1.4K]
First we solve what we can solve.
<span>y</span>-3= 2/3<span>(</span>x-1)
We first multiply
<span>y</span>-3= 2/3 (x) - 2/3
Then we move the -3 and it becomes +3 on the other side
y= 2/3 (x) - 2/3 + 3
And we solve what we can to get our answer.
y= 2/3 (x) + 2 1/3
3 0
3 years ago
Read 2 more answers
Which of the following is the solution for 6x + 3 ≤ 27
postnew [5]

Answer:

x  ≤  4

Step-by-step explanation:

6x + 3 ≤ 27        subtract 3 both sides

6x ≤ 24              divide 6 both sides

x ≤ 4                   There's your answer

5 0
3 years ago
Gravel is being dumped from a conveyor belt at a rate of 20 ft3 /min and its coarseness is such that it forms a pile in the shap
pantera1 [17]

Answer:

The height of the pile is increasing at the rate of  \mathbf{ \dfrac{20}{56.25 \pi}   \ \ \ \ \  ft/min}

Step-by-step explanation:

Given that :

Gravel is being dumped from a conveyor belt at a rate of 20 ft³ /min

i.e \dfrac{dV}{dt}= 20 \ ft^3/min

we know that radius r is always twice the   diameter d

i.e d = 2r

Given that :

the shape of a cone whose base diameter and height are always equal.

then d = h = 2r

h = 2r

r = h/2

The volume of a cone can be given by the formula:

V = \dfrac{\pi r^2 h}{3}

V = \dfrac{\pi (h/2)^2 h}{3}

V = \dfrac{1}{12} \pi h^3

V = \dfrac{ \pi h^3}{12}

Taking the differentiation of volume V with respect to time t; we have:

\dfrac{dV}{dt }= (\dfrac{d}{dh}(\dfrac{\pi h^3}{12})) \times \dfrac{dh}{dt}

\dfrac{dV}{dt }= (\dfrac{\pi h^2}{4} ) \times \dfrac{dh}{dt}

we know that:

\dfrac{dV}{dt}= 20 \ ft^3/min

So;we have:

20= (\dfrac{\pi (15)^2}{4} ) \times \dfrac{dh}{dt}

20= 56.25 \pi \times \dfrac{dh}{dt}

\mathbf{\dfrac{dh}{dt}= \dfrac{20}{56.25 \pi}   \ \ \ \ \  ft/min}

The height of the pile is increasing at the rate of  \mathbf{ \dfrac{20}{56.25 \pi}   \ \ \ \ \  ft/min}

8 0
3 years ago
Can someone help me
Vikki [24]

Answer:

5x + (x+12) = 90

x = 13

m∡1 = 5(13) = 65°

m∡2 = 13 + 12 = 25°

Step-by-step explanation:

6x + 12 = 90

6x = 78

x = 13

7 0
3 years ago
Solve for x, angle A, and Angle B<br> A x+50 B x+80 c72
jolli1 [7]
I’m assuming you man degrees? Are these angles of a triangle?

This doesn’t really make sense because the angles in a triangle add up to 180° so your equation would be x+50+x+80+72=180

Combine like terms to get
2x+202=180

Then subtract 202 from both sides
2x=-22

So x would be -11 which doesn’t seem right lol
7 0
3 years ago
Read 2 more answers
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