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Mashutka [201]
3 years ago
5

Which statements are true?

Mathematics
1 answer:
ludmilkaskok [199]3 years ago
3 0

Answer:

30x^4−12x^3=6x^3(5x−2) = True

4x^2+10x=2x(2x+5) = True

100x^3+5=5x^3(20x+1) = False

8x^3−6x=2x^3(4−3x3) = False

Step-by-step explanation:

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Rationalize the numerator. <br><img src="https://tex.z-dn.net/?f=%20%20%5Cfrac%7B%20%5Csqrt%5B3%5D%7B144x%20%7D%20%7D%7B%20%5Csq
Simora [160]

rationalizing the numerator, or namely, "getting rid of that pesky radical at the top".


we simply multiply top and bottom by a value that will take out the radicand in the numerator.


\bf \cfrac{\sqrt[3]{144x}}{\sqrt[3]{y}}~~&#10;\begin{cases}&#10;144=2\cdot 2\cdot 2\cdot 2\cdot 3\cdot 3\\&#10;\qquad 2^3\cdot 18&#10;\end{cases}\implies \cfrac{\sqrt[3]{2^3\cdot  18x}}{\sqrt[3]{y}}\implies \cfrac{2\sqrt[3]{  18x}}{\sqrt[3]{y}}&#10;\\\\\\&#10;\cfrac{2\sqrt[3]{  18x}}{\sqrt[3]{y}}\cdot \cfrac{\sqrt[3]{(18x)^2}}{\sqrt[3]{(18x)^2}}\implies \cfrac{2\sqrt[3]{(18x)(18x)^2}}{\sqrt[3]{(y)(18x)^2}}\implies \cfrac{2\sqrt[3]{(18x)^3}}{\sqrt[3]{18^2x^2y}}


\bf \cfrac{2(18x)}{\sqrt[3]{324x^2y}}~~&#10;\begin{cases}&#10;324=2\cdot 2\cdot 3\cdot 3\cdot 3\cdot 3\\&#10;\qquad 12\cdot 3^3&#10;\end{cases}\implies \cfrac{36x}{\sqrt[3]{12\cdot 3^3x^2y}}&#10;\\\\\\&#10;\cfrac{36x}{3\sqrt[3]{12x^2y}}\implies \cfrac{12x}{\sqrt[3]{12x^2y}}

3 0
3 years ago
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Can someone please show me only how to do the number 6 through 9 step by step number bonds it’s so confuse to me please
KengaRu [80]

Answer:

I think it's just 2 numbers you add together to get that number. for example number 6 you could add 10 and 5 in the circles to get 15 then you add 15 and 4 to get 19

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Nutka1998 [239]
Yes
7x6=42
8x6=48
Hope that helped :D
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5 0
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Help pleaseeeee????????
rodikova [14]
Answer is C sir......
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3 years ago
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