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3 years ago

Which set of points is a function?

Mathematics

2 answers:

mariarad [96]3 years ago

6 0

I think its A sorry if im wrong

Nuetrik [128]3 years ago

4 0

The answer is B) {1,2),(2,2),(3,2)

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Solve 7(x-6)<4(2x-1)

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Answer: x > -38

Step-by-step explanation:

7x - 42 < 8x - 4

-38 < x

x > -38

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3 years ago

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Which expression is equivalent 24 + 30

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Answer:

23 + 31

Step-by-step explanation:

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3 years ago

What is the sum of (8a+2b-4) and (3b-5)

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Answer:

8a+5b-9

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(8a+2b-4)+(3b-5)

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3 years ago

Is 24/6 only a rational number

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3 years ago

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The first terms of an infinite geometric sequence, Un are 2, 6, 18, 54... The first terms of a second infinite geometric sequenc

gladu [14]

Answer:

r = 9 and m = 112

Step-by-step explanation:

$\sum_{k=1}^{225}W_{k}=\sum_{k=0}^{m}4r^{k}$

Write W in terms of U and V.

$\sum_{k=1}^{225}(U_{k}+V_{k})=\sum_{k=0}^{m}4r^{k}\\\sum_{k=1}^{225}U_{k}+\sum_{k=1}^{225}V_{k}=\sum_{k=0}^{m}4r^{k}$

Define U and V using geometric series formula.

$\sum_{k=1}^{225}2(3)^{k-1}+\sum_{k=1}^{225}2(-3)^{k-1}=\sum_{k=0}^{m}4r^{k}$

Use sum of geometric series formula.

$2(\frac{1-(3)^{225}}{1-3})+2(\frac{1-(-3)^{225}}{1-(-3)})=4(\frac{1-(r)^{m+1}}{1-r})$

Simplify.

$-1(1-3^{225})+\frac{1+3^{225}}{2}=4(\frac{1-(r)^{m+1}}{1-r})\\-1+3^{225}+\frac{1}{2}+\frac{3^{225}}{2}=4(\frac{1-(r)^{m+1}}{1-r})\\-\frac{1}{2}+\frac{3(3^{225})}{2}=4(\frac{1-(r)^{m+1}}{1-r})\\\frac{-1+3(3^{225})}{2}=4(\frac{1-(r)^{m+1}}{1-r})\\\frac{-1+3^{226}}{2}=4(\frac{1-(r)^{m+1}}{1-r})\\4\frac{-1+3^{226}}{8}=4(\frac{1-(r)^{m+1}}{1-r})\\4\frac{1-3^{226}}{-8}=4(\frac{1-(r)^{m+1}}{1-r})\\4\frac{1-9^{113}}{1-9}=4(\frac{1-(r)^{m+1}}{1-r})$

Therefore, r = 9 and m = 112.

8 0

3 years ago