X² + 6x -12 = 0
x = <u>-(6) +/- √((6)² - 4(1)(-12))</u>
2(1)
x = <u>-6 +/- √(36 + 48)</u>
2
x = <u>-6 +/- √(84)
</u> 2<u>
</u>x = <u>-6 +/- 2√(21)
</u> 2<u>
</u>x = -3 <u>+</u> √(21)
x = -3 + √(21) x = -3 - √(21)
Answer:
(i)
y-intercept is -2
(ii)
slope is 
(iii)
slope is positive
(iv)
another point is (3,0)
Step-by-step explanation:
We are given equation as

now, we can compare it with slope intercept form of line
y=mx+b
where
m is slope
b is y-intercept
we get


So,
(i)
y-intercept is -2
(ii)
slope is 
(iii)
we can see that

is a fraction and positive
so, slope is positive
(iv)
we can select any random value of x and find y
that will give us second point
Let's assume
x=3



So, another point is (3,0)
(v)
Graph: