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guapka [62]
3 years ago
11

in a first aid kit the ratio of large bandages to small bandages is 5 to 2. Based on this ratio, how many large bandages are in

the kit if there are total of 60 bandages?
Mathematics
1 answer:
Radda [10]3 years ago
5 0
The best way to answer this question is to set up the first sentence as a ratio of large bandages to total bandages. You would write 5 large bandages to 7 total bandages to 7 total bandages.  Then you would make this equivalent to x number of large bandages to 60 total.  It would look like this 5:7 = x:60.  You could use cross products to multiply 60 by 5 to get 300.  7 times x also should equal 300.  Unfortunately, this example will not leave us with a whole number of bandages, but 300/7 is a repeating decimal or a mixed number (42 6/7 large bandages). 
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The perimeter of a parallelogram is 72 meters.The width of the parallelogram is four meters less than its length. Find the lengt
Naya [18.7K]
Parallelogram have 4 sides.

Use the distributive property. 2 multiply the last and negative 4 in the parentheses.
2l + 2(l - 4) = 72 m

Combine Like terms
2l + 2l - 8 = 72 m
4l - 8 = 72 m
Get l all by itself by adding 8 to both sides
4l - 8 = 72 m
+8. +8

Divide both sides by 4
4l = 80
4. 4

l= 20

The width of the parallelogram is four meters less than its length.

4 sides
2 length = 20
2 width = 16

I got 16 by subtracting 4 from 20

Comment if you need any other help :)
4 0
3 years ago
Plz help me with it !
Kipish [7]

Answer:   \bold{-7+2\sqrt{14}+5\sqrt{7}-10\sqrt{2}}

<u>Step-by-step explanation:</u>

\dfrac{\sqrt7-5}{\sqrt7+\sqrt8}\bigg(\dfrac{\sqrt7-\sqrt8}{\sqrt7-\sqrt8}\bigg)=\dfrac{7-2\sqrt{14}-5\sqrt{7}+10\sqrt2}{7-8}=\dfrac{7-2\sqrt{14}-5\sqrt{7}+10\sqrt2}{-1}\\\\\\=\boxed{-7+2\sqrt{14}+5\sqrt{7}-10\sqrt2}

8 0
3 years ago
The price of a cycle is reduced by 25 per cent. The new price is reduced by a further 20 per cent.Find the single reduction the
Evgen [1.6K]

Answer:

40%  . The single reduction together is 40%.

Step-by-step explanation:

Let the bicycle cost is   x before reduced price.

First 25% is reduced  and again 20% further reduced.

Let the single reduction is y% if the two reduction together are equal.

Solution,

Case .1

reduction cost=x\times 25%%

=x\times 25/100

=x/4

The cost of bicycle after reduction of 25% is

=x-x/4=3x/4

cost of reduction further reduction of 20%      =3x/4\times 20%

=3x\times 20/(4\times 100)

=3x/20

The new cost of bicycle is further reduction of 20% is

=3x/4-3x/20

=\left ( 15x-3x \right )/20

=12x/20=3x/5

Case.2

if single reduction is done new cost of cycle is equal

x-x\times y%=3x/5

x\left ( 1-y/100 \right )=3x/5

\left ( 100-y \right )/100=3/5

100-y=60

y=40%

single reduction of a cycle is 40%

8 0
3 years ago
PLEEEAAASSSEEE HELLLP
mestny [16]
Y = -x +8 is the answer for this one.
8 0
4 years ago
Thanks in advance for the answer
soldier1979 [14.2K]
2^{-2} =  \frac{1}{2^{2}} = \frac{1}{4} &#10;

does this make sense to you? Do you have any questions about raising numbers to a negative value?
5 0
3 years ago
Read 2 more answers
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