Given the Point G is (-8,6) if Point J is a reflection of point G and is reflected across the x axis, to get the coordinate of point J, we will negate the y coordinate while retaining the x coordinate value

J = (-8, -(6))

J = (-8, -6)

Hence the required coordinate of J is (-8, -6)

7 0

2 years ago

Please tell me the function( will mark as brainiest) thanks

Alecsey [184]

Answer:

y = 8x+8

Step-by-step explanation:

We can solve for the function by finding the slope of the linear function using two points. Let's use (0,8) and (1,16)

Slope formula is: $m = \frac{y2-y1}{x2-x1}$

Plug in the 2 points: $m = \frac{16-8}{1-0}$

Simplify: m = 8

So now, for the equation y = mx+b, we have m which is y = 8x+b

Now we need to find b by using another point from this linear function.

We can use the point (2,24).

Plug this point into the equation y = 8x+b

24 = 8(2)+b
24 = 16 + b
b = 8

We have now found the equation of the linear function: y = 8x+8

6 0

3 years ago