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2 years ago

Bernie's car used 100 cups of gasoline during a drive he paid 3.12 per gallon for gas how much does it gas cost

Mathematics

1 answer:

Lera25 [3.4K]2 years ago

3 0

Answer:

19.50

Step-by-step explanation:

There are 16 cups in a gallon. Divide 100 into 16 to get 6.25. You now just multiply 3.12 by 6.25 to get 19.5. Your answer is $19.50.

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Let A = {10, 20, 30, 40, 50, 60} and B = {10, 40, 603. What is AnB

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Answer: I DONT KNOW
Explanation: SORRY

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3 years ago

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Assume that the sales of a certain appliance dealer can be approximaed y sraig were $6000 in 1982 and $ 64,000 in 1987. Let x -

viktelen [127]

Answer:

$y=11,600x+6,000$

Yearly sales in 1990: $98,800.

Step-by-step explanation:

We have been given that the sales of a certain appliance dealer can be approximated by a straight line. Sales were $6000 in 1982 and $ 64,000 in 1987.

If at 1982, $x=0$ then at 1987 x will be 5.

Now, we have two points (0,6000) and (5,64000).

$\text{Slope}=\frac{64,000-6,000}{5-0}$

$\text{Slope}=\frac{58,000}{5}$

$\text{Slope}=11,600$

Now, we will represent this information in slope-intercept form of equation.

$y=mx+b$ , where,

m = Slope,

b = Initial value or y-intercept.

We have been given that at $x=0$ , the value of y is 6,000, so it will be y-intercept.

Substitute values:

$y=11,600x+6,000$

Therefore, the equation $S=11,600x+6,000$ represents yearly sales.

Now, we will find difference between 1990 and 1982.

$1990-1982=8$

To find yearly sales in 1990, we will substitute $x=8$ in the equation.

$S=11,600(8)+6,000$

$S=92,800+6,000$

$S=98,800$

Therefore, the yearly sales in 1990 would be $98,800.

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2 years ago

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Y=3x+4 is the equation you are looking for!

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You had $20 to spend on seven avocados. After buying them you had $6. How much did each avocado cost?

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2 years ago

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Find the area of the shaded region. Round to the nearest tenth.

AURORKA [14]

Answer:

3.5 square cm

Step-by-step explanation:

$Area \: of \: both \: squares \\ = {2}^{2} + {3}^{2} \\ = 4 + 9 \\ = 13 \: {cm}^{2} \\ \\ Area \: of \: both \: right \: \triangle s \\ = \frac{1}{2} \times (2 + 3) \times 2 + \frac{1}{2} \times3 \times 3 \\ = 5 \times 1+ 1.5 \times 3 \\ = 5 + 4.5 \\ = 9.5 \: {cm}^{2} \\ \\ Area \: of \:shaded \: region \\ = Area \: of \: both \: squares\\ - Area \: of \: both \: right \: \triangle s \\ = 13 - 9.5 \\ \purple { \boxed{ \bold{Area \: of \:shaded \: region = 3.5 \: {cm}^{2} }}}$

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3 years ago