The addition of sodium bicarbonate to carbon treatments is fundamental because this substance has buffer properties.
<h3>What is a buffer?</h3>
In chemistry, a buffer is any substance that may act both as an acid or base in a given solution.
Sodium bicarbonate is a fundamental buffer in biological systems because it may prevent different types of homeostatic imbalances (e.g., acidosis).
In conclusion, the addition of sodium bicarbonate to carbon treatments is fundamental because this substance has buffer properties.
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beef because beef is very important to poop and poop is important to beef and poop plus beef equald diarrhea
North/South America:
New World monkeys inhabit the New World, which includes North and South America.
Africa and Asia:
Prosimians, the earliest of the primates, inhabit regions of Africa and Asia.
Old World monkeys still live in Africa and Asia. Fossil species also lived in Europe.
Apes are Old World primates. They are found today in Africa and Asia.
<h3>What is the group of Primates?</h3>
The primates are;
- New World monkeys
- Prosimians
- Old World monkeys
- Apes
The groups are;
North/South America
Africa and Asia
New World monkeys inhabit the New World, which includes North and South America.
Prosimians, the earliest of the primates, inhabit regions of Africa and Asia. This also applies to Apes and Old monkeys.
Thus;
North/South America:
New World monkeys inhabit the New World, which includes North and South America.
Africa and Asia:
Prosimians, the earliest of the primates, inhabit regions of Africa and Asia.
Old World monkeys still live in Africa and Asia. Fossil species also lived in Europe.
Apes are Old World primates. They are found today in Africa and Asia.
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At the bottom of the circle, the ball is being pulled upward by tension in the rope and downward by its own weight, so that the net force on it is
∑ F = 450 N - (0.75 kg) g = (0.75 kg) a
where a is centripetal acceleration. At this maximum tension, the ball has a maximum centripetal acceleration of
a = (450 N - (0.75 kg) g) / (0.75 kg) = 590.2 m/s²
Then its maximum tangential speed v is such that
a = v² / (1.0 m)
⇒ v = √((1.0 m) a) ≈ 25 m/s
