Answer:
m<1 = 57°
m<2 = 33°
Step-by-step explanation:
To find the numerical measure of both angles, let's come up with an equation to determine the value of x.
Given that m<1 = (10x +7)°, and m<2 = (9x - 12)°, where both are complementary angles, therefore, it means, both angles will add up to give us 90°.
Equation we can generate from this, is as follows:
(10x + 7)° + (9x - 12)° = 90°
Solve for x
10x + 7 + 9x - 12 = 90
Combine like terms
19x - 5 = 90
Add 5 to both sides
19x = 90 + 5 (addition property not equality)
19x = 95
Divide both sides by 19
x = 5
m<1 = (10x +7)°
Replace x with 5
m<1 = 10(5) + 7 = 50 + 7 = 57°
m<2 = (9x - 12)
Replace x with 5
m<2 = 9(5) - 12 = 45 - 12 = 33°
Use this version of the Law of Cosines to find side b:
b^2 = a^2 + c^2 − 2ac cos(B)
We want side b.
b^2 = (41)^2 + (20)^2 - 2(41)(20)cos(36°)
After finding b, you can use the Law of Sines to find angles A and C or use other forms of the Law of Cosines to find angles A and C.
Try it....
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Answer:
Step-by-step explanation:
angles in triangle = 180
1. 180 - (70+45) = x = 65
2. x = 35
180 - 110 = 70
70/2 = 35 (isosceles triangle)
3. x = 113, y = 67
180 - (62 + 51) = y = 67
Angles on a line = 180
180 - 67 = x = 113
4. x = 60, y = 50
x = 180 - 120 = 60
y = 180 - (60 + 70) = 50
answers in degrees.
Eliminate x's
multiply 2nd equation by -2 ad add to first
2x+3y=9
<u>-2x-10y=-16 +</u>
0x-7y=-7
-7y=-7
divide by -7
y=1
sub back
2x+3y=9
2x+3(1)=9
2x+3=9
minus 3
2x=6
divide 2
x=3
x=3
y=1
(x,y)
(3,1)
D