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Anvisha [2.4K]
4 years ago
13

I’m just really sleep deprived sorry 25/2 x 85/5

Mathematics
2 answers:
mixas84 [53]4 years ago
5 0
It is definitely 212.5
Katena32 [7]4 years ago
4 0
Your answer is 212.5
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A pumpkin is launched directly upwards at 72 feet per second from a platform 12 feet high. The pumpkin's height, h, at time t se
Illusion [34]

Answer:

93 feet

Step-by-step explanation:

Let us first find the time it takes to reach the maximum height. We can do this by differentiating the height function to get velocity:

dh(t)/dt = v(t) = -32t + 72

The maximum height will occur when the velocity becomes 0. Therefore, the time it takes to reach maximum height is:

0 = -32t + 72

32t = 72

t = 72/32 = 2.25 seconds

Therefore, the maximum height of the pumpkin is:

h(2.25) = -16(2.25)^2 + 72(2.25) + 12

h(2.25) = -81 + 162 + 12

h = 93 feet

4 0
3 years ago
What is the solution to the equation 3 + = 4? y = y = y = 1 y = 4
kvv77 [185]

Answer:

y = 1

Step-by-step explanation:

3 + y = 4

y = 1

6 0
3 years ago
Read 2 more answers
What is 11 times one fourth
max2010maxim [7]

Answer: 2 and three-fourths (2 3/4)

Step-by-step explanation:

11 * 1/4

1/4 = 0.25

0.25 * 11 = 2.75

.75 = 3/4

2.75 = 2 3/4

6 0
4 years ago
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A rec Eric Tangler prism as shown to have of 4 cm x 2 cm x 3 cm area
spayn [35]
4 = Length
2 = Width
3 = Height

4x2x3=24 cm square
5 0
3 years ago
Some types of algae have the potential to cause damage to river ecosystems. Suppose the accompanying data on algae colony densit
Alex Ar [27]

Answer:

y=-2.86 x +228.84

Step-by-step explanation:

We assume that the data is this one:

x: 50, 55, 50, 79, 44, 37, 70, 45, 49

y: 152, 53, 22, 35, 38, 166, 13, 185, 25

Find the least-squares line appropriate for this data.  

For this case we need to calculate the slope with the following formula:

m=\frac{S_{xy}}{S_{xx}}

Where:

S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i)}{n}

S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}

So we can find the sums like this:

\sum_{i=1}^n x_i = 50+ 55+ 50+ 79+ 44+ 37 +70+ 45+ 49=479

\sum_{i=1}^n y_i =152 + 53 + 22 + 35 + 38 + 166 + 13 + 185 + 25=689

\sum_{i=1}^n x^2_i =50^2 + 55^2 + 50^2 + 79^2 + 44^2 + 37^2 + 70^2 + 45^2 + 49^2=26897

\sum_{i=1}^n y^2_i =152^2 + 53^2 + 22^2 + 35^2 + 38^2 + 166^2 + 13^2 + 185^2 + 25^2=91641

\sum_{i=1}^n x_i y_i =50*152+ 55*53+ 50*22+ 79*35+ 44*38+ 37*166 +70*13+ 45*185+ 49*25=32654

With these we can find the sums:

S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}=26897-\frac{479^2}{9}=1403.56

S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i)}{n}=32654-\frac{479*689}{9}=-4016.11

And the slope would be:

m=-\frac{4016.11}{1403.56}=-2.86

Nowe we can find the means for x and y like this:

\bar x= \frac{\sum x_i}{n}=\frac{479}{9}=53.22

\bar y= \frac{\sum y_i}{n}=\frac{689}{9}=76.56

And we can find the intercept using this:

b=\bar y -m \bar x=76.56-(-2.86*53.22)=228.84

So the line would be given by:

y=-2.86 x +228.84

8 0
4 years ago
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