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Alika [10]
3 years ago
6

A pumpkin is launched directly upwards at 72 feet per second from a platform 12 feet high. The pumpkin's height, h, at time t se

conds can be represented by the equation h(t)= -16t^2+72t+12. Find the maximum height of the pumpkin and the time it takes to reach it.
Mathematics
1 answer:
Illusion [34]3 years ago
4 0

Answer:

93 feet

Step-by-step explanation:

Let us first find the time it takes to reach the maximum height. We can do this by differentiating the height function to get velocity:

dh(t)/dt = v(t) = -32t + 72

The maximum height will occur when the velocity becomes 0. Therefore, the time it takes to reach maximum height is:

0 = -32t + 72

32t = 72

t = 72/32 = 2.25 seconds

Therefore, the maximum height of the pumpkin is:

h(2.25) = -16(2.25)^2 + 72(2.25) + 12

h(2.25) = -81 + 162 + 12

h = 93 feet

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scZoUnD [109]

Answer:

(D) 1+0.06m

Step-by-step explanation:

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(B)= $127.2

(C)= $127.2

(D)= $8.2

As you can see after I substituted in 120 for (m) and solved, D is the only equation that did not represent her current balance.

I hope this helps!

3 0
3 years ago
Read 2 more answers
A farmer has 520 feet of fencing to construct a rectangular pen up against the straight side of a barn, using the barn for one s
Setler [38]

Answer:

310\text{ feet and }210\text{ feet}

Step-by-step explanation:

GIVEN: A farmer has 520 \text{ feet} of fencing to construct a rectangular pen up against the straight side of a barn, using the barn for one side of the pen. The length of the barn is 310 \text{ feet}.

TO FIND: Determine the dimensions of the rectangle of maximum area that can be enclosed under these conditions.

SOLUTION:

Let the length of rectangle be x and y

perimeter of rectangular pen =2(x+y)=520\text{ feet}

                                                x+y=260

                                               y=260-x

area of rectangular pen =\text{length}\times\text{width}

                                       =xy

putting value of y

=x(260-x)

=260x-x^2

to maximize \frac{d \text{(area)}}{dx}=0

260-2x=0

x=130\text{ feet}

y=390\text{ feet}

but the dimensions must be lesser or equal to than that of barn.

therefore maximum length rectangular pen =310\text{ feet}

                              width of rectangular pen =210\text{ feet}

Maximum area of rectangular pen =310\times210=65100\text{ feet}^2

Hence maximum area of rectangular pen is 65100\text{ feet}^2 and dimensions are 310\text{ feet and }210\text{ feet}

5 0
3 years ago
What is the diameter of a circle with a circumference of 176 feet use for 22 over for pie
Ipatiy [6.2K]
Formula for Diameter: <span>2 x radius
Formula for Radius:  R= C/2(pi)</span>
R= 176/2(22/7)
R=28.01
2(28.01)=56.02

Answer= 56.02


7 0
3 years ago
What is the area of the following trapezoid in square feet?
tangare [24]

Answer:

82.5 ft²

Step-by-step explanation:

The area (A) of a trapezoid is calculated as

A = \frac{1}{2} h (b₁ + b₂)

where h is the perpendicular height and b₁, b₂ the parallel bases

Here h = 7.5, b₁ = 7 and b₂ = 15 , then

A = \frac{1}{2} × 7.5 × (7 + 15) = 0.5 × 7.5 × 22 = 82.5 ft²

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3 years ago
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Answer:

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Step-by-step explanation:

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