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NISA [10]
3 years ago
10

What r the answers for 16 - 23??

Mathematics
2 answers:
erma4kov [3.2K]3 years ago
7 0
Hi!
the answer for 16 - 23 is -7
liq [111]3 years ago
3 0
The exponents are too small to be read<span />
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How much simple interest does 2560 earn in 17 months at a rate of 1 1/8
Tatiana [17]

Answer:185.87

Step-by-step explanation:

Explanation:

simple interest (SI) can be calculated using the formula

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

∣

∣

∣

2

2

S

I

=

P

R

T

100

2

2

∣

∣

∣

−−−−−−−−−−−−−−−

where P is the Principal, that is amount of money

R is the rate of interest

T is time in years

here P

=

$

2560

,

R

=

5

1

8

=

41

8

and T

=

17

12

years

⇒

S

I

=

2560

×

41

8

×

17

12

100

⇒

S

I

=

2560

×

41

×

17

100

×

8

×

12

⇒

S

I

≈

$

185.87

to nearest cent

4 0
3 years ago
Which of the following numbers is irrational?
skelet666 [1.2K]

Answer:

D          

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
In the above bridge, line segment BD is the perpendicular bisector of line segment AC. For the bridge to be safe, Triangle ABD i
klasskru [66]

Answer: we can get the sequence of reasons with help of below explanation.

Step-by-step explanation:

Here It is given that, line segment BD is the perpendicular bisector of line segment AC. ( shown in below diagram)

By joining points B with A and B with C ( Construction)

We get two triangles ABD and CBD.

We have to prove that : Δ ABD ≅ Δ CBD

      Statement                                                  Reason

1. AD ≅ DC                                    1. By the property of segment bisector

2. ∠BDA ≅ ∠ BDC                        2. Right angles

3. BD ≅ BD                                   3. Reflexive

4.  Δ ABD ≅ Δ CBD                      4. By SAS postulate of congruence


8 0
3 years ago
Consider the following region R and the vector field F. a. Compute the​ two-dimensional curl of the vector field. b. Evaluate bo
Shalnov [3]

Looks like we're given

\vec F(x,y)=\langle-x,-y\rangle

which in three dimensions could be expressed as

\vec F(x,y)=\langle-x,-y,0\rangle

and this has curl

\mathrm{curl}\vec F=\langle0_y-(-y)_z,-(0_x-(-x)_z),(-y)_x-(-x)_y\rangle=\langle0,0,0\rangle

which confirms the two-dimensional curl is 0.

It also looks like the region R is the disk x^2+y^2\le5. Green's theorem says the integral of \vec F along the boundary of R is equal to the integral of the two-dimensional curl of \vec F over the interior of R:

\displaystyle\int_{\partial R}\vec F\cdot\mathrm d\vec r=\iint_R\mathrm{curl}\vec F\,\mathrm dA

which we know to be 0, since the curl itself is 0. To verify this, we can parameterize the boundary of R by

\vec r(t)=\langle\sqrt5\cos t,\sqrt5\sin t\rangle\implies\vec r'(t)=\langle-\sqrt5\sin t,\sqrt5\cos t\rangle

\implies\mathrm d\vec r=\vec r'(t)\,\mathrm dt=\sqrt5\langle-\sin t,\cos t\rangle\,\mathrm dt

with 0\le t\le2\pi. Then

\displaystyle\int_{\partial R}\vec F\cdot\mathrm d\vec r=\int_0^{2\pi}\langle-\sqrt5\cos t,-\sqrt5\sin t\rangle\cdot\langle-\sqrt5\sin t,\sqrt5\cos t\rangle\,\mathrm dt

=\displaystyle5\int_0^{2\pi}(\sin t\cos t-\sin t\cos t)\,\mathrm dt=0

7 0
3 years ago
Nate solve the problem 3×5 = 15 by writing and solving 15÷5 = 3 explain why Nate method works
dmitriy555 [2]
It's shust the opposite
6 0
3 years ago
Read 2 more answers
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