First, for end behavior, the highest power of x is x^3 and it is positive. So towards infinity, the graph will be positive, and towards negative infinity the graph will be negative (because this is a cubic graph)
To find the zeros, you set the equation equal to 0 and solve for x
x^3+2x^2-8x=0
x(x^2+2x-8)=0
x(x+4)(x-2)=0
x=0 x=-4 x=2
So the zeros are at 0, -4, and 2. Therefore, you can plot the points (0,0), (-4,0) and (2,0)
And we can plug values into the original that are between each of the zeros to see which intervals are positive or negative.
Plugging in a -5 gets us -35
-1 gets us 9
1 gets us -5
3 gets us 21
So now you know end behavior, zeroes, and signs of intervals
Hope this helps<span />
Answer:
can be factored out as: 
Step-by-step explanation:
Recall the formula for the perfect square of a binomial :

Now, let's try to identify the values of
and
in the given trinomial.
Notice that the first term and the last term are perfect squares:

so, we can investigate what the middle term would be considering our
, and
:

Therefore, the calculated middle term agrees with the given middle term, so we can conclude that this trinomial is the perfect square of the binomial:

Answer:
The statement is true for every n between 0 and 77 and it is false for 
Step-by-step explanation:
First, observe that, for n=0 and n=1 the statement is true:
For n=0: 
For n=1: 
From this point we will assume that 
As we can see,
and
. Then,

Now, we will use the formula for the sum of the first 4th powers:

Therefore:

and, because
,

Observe that, because
and is an integer,

In concusion, the statement is true if and only if n is a non negative integer such that 
So, 78 is the smallest value of n that does not satisfy the inequality.
Note: If you compute
for 77 and 78 you will obtain:
You can think of this question like the photo attached above.
Hi!
I think for b, the answer would be:
You can construct an angle that is one fourth the measure of angle JKL, by dividing angle either angle MKL or JKM in half.
This is because one-fourth is also equal to one quarter (1/4). If you split angle JKL into 4 equal angles, you would have an angle that is one-fourth the measure (original angle) of angle JKL.
I think for c, the answer would be:
You can construct a 15 degree angle from a given 60 degree angle, by dividing the 60 degree angle into 4 equal angles.
This would work, because each of the 4 angles would be 15 degrees.
Hope this helps! Best of luck!
Answer:
1/5
Step-by-step explanation:
Gradient is another word for slope. To find the gradient, we have to use a formula.