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Gnom [1K]
2 years ago
8

(14-8) × (15-4) Use the order of operations to find the value of each expression

Mathematics
1 answer:
Yuliya22 [10]2 years ago
5 0

Answer:

66

Step-by-step explanation:

the order of operations is the acronym PEMDAS which stands for:

P: Parentheses

E: Exponents

M & D: Multiplication and Division

A & S: Addition and Subtraction

we do these in order, from left to right in the equation

for the equation (14 - 8) x (15 - 4), we would start with solving the parentheses

there are 2 sets of parentheses, so we will go from left to right in solving it:

(14 - 8) = 6

(15 - 4) = 11

we replace the values we have found from the parentheses into the equation

6 x 11

now we go through the list

we can already eliminate exponents because there are none in this equation

the next step is multiplication & division, in this equation there is only multiplication, so we multiply 6 x 11 which gives us the answer 66

there is nothing left for us to do at this point, so 66 is our final answer

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If a number has an infinite amount of 0's on the end of it, can I shorten it to just one 0?
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3 years ago
Two boys decided to buy a computer. The second boy had 5/6 of the money the first had. The first boy had 7/8 of the price of the
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Answer:

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Step-by-step explanation:

Let the price of the computer be $x

The first boy boy had 7/8 of this amount, the amount he has is thus 7/8 × $x = 7x/8

The second boy had 5/6 of what the first boy had. The amount of money he has is thus 5/6 × 7x/8 = 35x/48

Now, the addition of what they have is $696 more than what they need to pay. This amount is x+ 696

Mathematically, this can be represented as;

7x/8 + 35x/48 = x + 696

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77x - 48x = 33408

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7 0
3 years ago
Last​ year, a person wrote 126 checks. Let the random variable x represent the number of checks he wrote in one​ day, and assume
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Answer:  The mean number of checks written per​ day  =0.3452

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Assume that the year is not a leap year.

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\lambda=\dfrac{126}{365}\approx0.3452

Since , the distribution is Poisson distribution , then the variance must equal to the mean value i.e. \sigma^2=\lambda=0.3452

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