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3 years ago

(14-8) × (15-4) Use the order of operations to find the value of each expression

Mathematics

1 answer:

Yuliya22 [10]3 years ago

5 0

Answer:

Step-by-step explanation:

the order of operations is the acronym PEMDAS which stands for:

P: Parentheses

E: Exponents

M & D: Multiplication and Division

A & S: Addition and Subtraction

we do these in order, from left to right in the equation

for the equation (14 - 8) x (15 - 4), we would start with solving the parentheses

there are 2 sets of parentheses, so we will go from left to right in solving it:

(14 - 8) = 6

(15 - 4) = 11

we replace the values we have found from the parentheses into the equation

6 x 11

now we go through the list

we can already eliminate exponents because there are none in this equation

the next step is multiplication & division, in this equation there is only multiplication, so we multiply 6 x 11 which gives us the answer 66

there is nothing left for us to do at this point, so 66 is our final answer

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3 years ago

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2 years ago

Find an equation of the line through these points (15,2.2) (5,1.6). Write answer in a slope-intercept form

nadya68 [22]

Answer:

$y=\frac{\displaystyle 3}{\displaystyle 50}x+\frac{\displaystyle 13}{\displaystyle 10}$

Step-by-step explanation:

Hi there!

Slope-intercept form: $y=mx+b$ where $m$ is the slope and $b$ is the y-intercept (the value of y when x is 0)

1) Determine the slope (m)

$m=\frac{\displaystyle y_2-y_1}{\displaystyle x_2-x_1}$ where two given points are $(x_1,y_1)$ and $(x_2,y_2)$

Plug in the given points (15,2.2) and (5,1.6):

$m=\frac{\displaystyle 1.6-2.2}{\displaystyle 5-15}\\\\m=\frac{\displaystyle -0.6}{\displaystyle -10}\\\\m=\frac{\displaystyle 0.6}{\displaystyle 10}\\\\m=\frac{\displaystyle 0.3}{\displaystyle 5}\\\\m=\frac{\displaystyle 3}{\displaystyle 50}$

Therefore, the slope of the line is $\frac{\displaystyle 3}{\displaystyle 50}$ . Plug this into $y=mx+b$ :

$y=\frac{\displaystyle 3}{\displaystyle 50}x+b$

2) Determine the y-intercept (b)

$y=\frac{\displaystyle 3}{\displaystyle 50}x+b$

Plug in a given point and solve for b:

$1.6=\frac{\displaystyle 3}{\displaystyle 50}(5)+b\\\\1.6=\frac{\displaystyle 3}{\displaystyle 10}+b\\\\1.6-\frac{\displaystyle 3}{\displaystyle 10}=\frac{\displaystyle 3}{\displaystyle 10}+b-\frac{\displaystyle 3}{\displaystyle 10}\\\\\frac{\displaystyle 13}{\displaystyle 10}=b$