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1 year ago

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5. Calculate dimension: (A)

1 answer:

uranmaximum [27]1 year ago

6 0

The dimension A is 7.703

<h3>How to determine the dimension A?</h3>

The figure that completes the question is added as an attachment

From the attached figure, the lengths that make up the side A have the following measures:

1.031, 5.625 and 1.047

Add these measures to determine the dimension A

A = 1.031 + 5.625 + 1.047

Evaluate the sum

A = 7.703

Hence, the dimension A is 7.703

Read more about dimensions at

brainly.com/question/19819849

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What is the result of a dilation of scale factor 3 centered at the origin of the line 2y + 3x=10?? PLEASE HELP PLEASEEEEEEEEE

maks197457 [2]

Given:

The equation of a line is:

$2y+3x=10$

The line is dilated by factor 3.

To find:

The result of dilation.

Solution:

The equation of a line is:

$2y+3x=10$

For $x=0$ ,

$2y+3(0)=10$

$2y+0=10$

$y=\dfrac{10}{2}$

$y=5$

For $x=2$ ,

$2y+3(2)=10$

$2y+6=10$

$2y=10-6$

$2y=4$

Divide both sides by 2.

$y=\dfrac{4}{2}$

$y=2$

The given line passes through the two points A(0,5) and B(2,2).

If the line dilated by factor 3 with origin as center of dilation, then

$(x,y)\to (3x,3y)$

Using this rule, we get

$A(0,5)\to A'(3(0),3(5))$

$A(0,5)\to A'(0,15)$

Similarly,

$B(2,2)\to B'(3(2),3(2))$

$B(2,2)\to B'(6,6)$

The dilated line passes through the points A'(0,15) and B'(6,6). So, the equation of dilated line is:

$y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)$

$y-15=\dfrac{6-15}{6-0}(x-0)$

$y-15=\dfrac{-9}{6}(x)$

$y-15=\dfrac{-3}{2}x$

Multiply both sides by 2.

$2(y-15)=-3x$

$2y-30=-3x$

$2y+3x=30$

Therefore, the equation of the line after the dilation is $2y+3x=30$ .

3 0

2 years ago

Let P2 denote the vector space of all polynomials with degree less than or equal to 2. (a) Show that B = {1 + x + x 2 , 1 + 2x −

nirvana33 [79]

Answer:

The answer is in the the attachment

Step-by-step explanation:

The question you posted was incomplete but i believe below is the complete question;

Let P2 denote the vector space of all polynomials with degree less than or equal to 2. (

a) Show that B = {1 + x + x 2 , 1 + 2x − x 2 , 1 − 2x − x 2} is a basis for P2.

(b) Find the coordinate vector of p(x) = 1 + 2x + 3x 2 relative to the basis B

The answer is explained in the attachments.

7 0

3 years ago

The base of a solid in the xy-plane is the circle x2 + y2 = 16. Cross sections of the solid perpendicular to the y-axis are semi

Alexus [3.1K]

Answer:

The volume of the solid will be = 134.1 cubic units.

Step-by-step explanation:

The base of a solid has the equation of a circle x² + y² = 16 in the xy-plane. Cross-sections perpendicular to the y-axis of the solid are semicircles.

Therefore, the solid will be the shape of a hemisphere.

Now, the radius of the hemisphere will be 4 units.

{Since the base of the hemisphere is on the xy-plane and have equation

x² + y² = 4²}

Therefore, the volume of the solid will be = $\frac{2}{3}\pi r^{3} = (\frac{2}{3})\times (\frac{22}{7}) \times (4^{3}) = 134.1$ cubic units. (Answer)

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2 years ago

HELP ASAP 56 POINTS

Olegator [25]

Answer:

Step-by-step explanation:

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2 years ago

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HELPPPPPPPPPPPPPPPPWhich statements are true about the ordered pair(-1, -4) and the system of

Anastasy [175]

Answer:

When (-1,-4) is substituted into the second equation, the equation is true.

The ordered pair (-1,-4) is a solution to the system of linear equations.

When (-1,-4) is substituted into the first equation, the equation is true.

Step-by-step explanation:

Given

$x - y = 3$

$7x - y = -3$

Required

What is true about $(x,y) = (-1,-4)$

To do this, we substitute -1 for x and -4 for y in both equations;

For $x - y = 3$

$-1 - (-4) = 3$

$-1 + 4 = 3$

$3 = 3$

<em>Hence: </em> $(-1,-4)$ <em> is true for </em> $x - y = 3$ <em></em>

For $7x - y = -3$

$7(-1) - (-4) = -3$

$-7 +4 = -3$

$-3 = -3$

<em>Hence: </em> $(-1,-4)$ <em> is true for </em> $7x - y = -3$

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2 years ago