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maw [93]
2 years ago
12

50% of cakes where party cakes 1/5 where fruit the rest where sponge. what percentage where sponge.

Mathematics
2 answers:
andrew11 [14]2 years ago
8 0

Answer:

Let me answer this

1/5=20%, 50%+20%=70%

100%-70%= 30%

Delvig [45]2 years ago
7 0
1/5= 20%
50%+20% =70% total amount of party cakes and fruit cakes
subtraction 70% from 100% leaves 30% for the sponge cakes
answer is 30%

hope this helps

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A number is 6.14 what way represent the value of the 4 in 6.14
Lady_Fox [76]

Answer:

Step-by-step explanation:

the value of the 4 in 6.14 is 0.04.

this is because the 4, or in this case 0.04

is in the hundredths place. So it is

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5 0
3 years ago
21 and 14 Greatest common factor
myrzilka [38]

Answer: 7

Step-by-step explanation:

Find the prime factors of each term in order to find the greatest common factor (GCF).

7 0
2 years ago
Read 2 more answers
Please give the actual answer if you choose to anwser
zlopas [31]

9514 1404 393

Answer:

  C. 78°

Step-by-step explanation:

The sum of angles in a triangle is 180°.

  (7x-6)° +(4x+11)° +43° = 180°

  11x +48 = 180 . . . . . divide by °, simplify

  11x = 132 . . . . . . . subtract 48

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Then the measure of angle T is ...

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6 0
3 years ago
In a class in which the final course grade depends entirely on the average of four equally weighted 100-point tests, Joyce has s
d1i1m1o1n [39]

Answer:

66 ≤ f ≤100

Explanation

Mean= ( Σ x ) / n

Mean= sum of scores/ number of subject she took

Now, she already too 3 subject which sum is 85+83+86=254

Now we need to know range of score for her to have (grade) a mark between 80 and 89

Now let take the lower limit mean=80

The lowest score she can get is

Mean = ( Σx) / n

80=(85+83+86+f)/4

80×4= 254+f

Therefore, f= 320-254=66

Therefore the minimum score she can have to have a B is 66.

Then, let take the upper limit mean 89. i.e the maximum she can have so that she don't have an A grade.

Mean = ( Σx) / n

89=( 83+85+86+f)/4

89×4= 254+f

f= 356-254

f=102.

Therefore this shows that she cannot have an A grade in the exam. The maximum score for the exam is 100.

There the range of score is 66 ≤ f ≤100 to have a B grade

66 ≤ f ≤100 answer

Since she cannot score 102 in the examination.

8 0
3 years ago
There are 92,746 seats available for fans at UGA's Sanford Stadium. Auburn University's Jordan-Hare Stadium has seating for 87,4
Anvisha [2.4K]

Given :

Number of seats at UGA's Sanford Stadium, n_1 = 92,746 .

Number of seats at Auburn University's Jordan-Hare Stadium, n_2=87,451 .

To Find :

How many more seats are there at UGA's stadium.

Solution :

Extra seats at UGA's stadium = seats at UGA's Sanford Stadium - seats at    

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= 92,746 - 87,451

= 5295

Hence, this is the required solution.

4 0
2 years ago
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