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irinina [24]
2 years ago
10

Can someone help me

Mathematics
1 answer:
Alexxandr [17]2 years ago
6 0

Answer:

i) 0.1056

ii) 0.105

iii) 0.1

iv) 0.1056

Step-by-step explanation:

0.36, to the power of 2 (0.36×0.36) is 0.1296

0.1296-0.03×0.8=0.1056

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The length of a rectangle is x times the square root of 100. The width is one-half y more than three-halves x. Given that the ar
dimulka [17.4K]

Answer:

15x^2+5xy-125=0

Step-by-step explanation:

We are give the following in the question:

Dimensions of rectangle:

Length , l =

l = x\sqrt{100} = 10x

Width of rectangle, w =

w = \dfrac{y}{2} +\dfrac{3x}{2}

Area of rectangle = 125 square cm.

Area of rectangle =

A =l\times w

Putting values, we get,

125 = 10x\times (\dfrac{y}{2}+\dfrac{3x}{2})\\\\125 = 5xy+15x^2\\15x^2+5xy-125=0

is the required equation.

7 0
2 years ago
Read 2 more answers
PLEASE HELP :(!!!!!!!!
Levart [38]

Answer:

19/3 > square root of 37 > 6.08171 > 6.012

4 0
3 years ago
Find 2 integers whose sum is -7 and whose product is 1.2
RSB [31]
X = - 7 - y ( - 7 - y ) y = 12y = - 3 or y = - 4x = - 7 - ( - 3) or x = - 7 - ( - 4)( - 4, - 3)( - 3, - 4)
7 0
3 years ago
Explain why angle is considered a defined term in geometry.
77julia77 [94]

Answer:

An angle is considered a defined term in geometry because defined terms are terms that have a formal definition and can be defined using other geometrical terms.

Angle: Two rays that share the same endpoint, however, the rays take off in different directions. The area in the middle of the two rays is the angle measure.

5 0
3 years ago
Scores on the test are normally distributed with a mean of 79 and a standard deviation of 8.4. Find the numerical limits for a B
Oksanka [162]

This is not the question, the correct question is:

A humanities professor assigns letter grades on a test according to the following scheme. A: Top 6% of scores B: Scores below the top 6% and above the bottom 59% C: Scores below the top 41% and above the bottom 17% D: Scores below the top 83% and above the bottom 7% F: Bottom 7% of scores.

Scores on the test are normally distributed with a mean of 79 and a standard deviation of 8.4. Find the numerical limits for a B grade. Round your answers to the nearest whole number, if necessary.

Answer:  The numerical limits for grade B is 81 and 92

Step-by-step explanation:

Given that

mean Ж = 79

Standard deviation S = 8.4

B: Scores below the top 6% and above the bottom 59%

To find the numerical value for Grade B

Below the top bottom 6% ( 0.06) is

p ( X < Ж ) = 1 - 0.06

p ( X < Ж ) = 0.94

therefore

P( (X - ц)/S < (X - Ж) / S)) = 0.94

(X - 79) / 8.4 = 1.5548 ( from normal distribution table )

X - 79 = 13.0603

X = 13.0603 + 79

X = 92.06 ≈ 92 ( nearest whole number)

Above bottom 59% ( 0.59) is

p ( X < Ж ) = 0.59

therefore

P( (X - ц)/S < (X - Ж) / S)) = 0.59

(X - 79) / 8.4 = 0.2275 ( from normal distribution table )

X - 79 = 1.9114

X = 1.9114 + 79

X = 80.91 ≈ 81 ( nearest whole number)

So the numerical limits for grade B is 81 and 92

3 0
3 years ago
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