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NISA [10]
3 years ago
6

find out volume of the solid obtained by rotating the region bounded by the given curves about the specified line. y=lnx, y=1, y

=3,x=0; about the y-axis.

Mathematics
1 answer:
erik [133]3 years ago
7 0
Look\ at\ the\ picture.\\\\y=lnx\\\\x=lny\to e^x=e^{lny}\to y=e^x\\\\V=\int\limits_1^3\left(e^x\right)^2dx=(*)\\\\\int\left(e^x\right)^2dx=\int(e^x\times e^x)dx\Rightarrow  \left|\begin{array}{ccc}e^x=t\\\\e^x\ dx=dt\end{array}\right|\Rightarrow\int\limits_1^3t\ dt=\frac{1}{2}t^2=\frac{1}{2}\left(e^x\right)^2=\frac{e^{2x}}{2}

(*)=\left\frac{e^{2x}}{2}\right]^3_1=\frac{e^{2(3)}}{2}-\frac{e^{2(1)}}{2}=\frac{e^6-e^2}{2}\ (units)

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  (a)  vertical compression by a factor of 1/3

Step-by-step explanation:

We can see that g(x) = 1/3f(x). Multiplying a function by a constant scales the graph vertically by that factor. When the magnitude of the factor is more than 1, we say the graph is "stretched." When it is less than 1, we say the graph is "compressed" by that factor.

Here, the scale factor is 1/3, so the graph is "vertically compressed by a factor of 1/3."

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<em>Additional comment</em>

My <em>personal</em> preference is for compression to be described by the factor the graph is divided by. I would call g(x) a compression of f(x) by a factor of 3. Modern curriculum authors disagree, calling it compression by a factor of 1/3.

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