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andre [41]
3 years ago
11

HELP PLEASE!! Part A

Mathematics
1 answer:
andrey2020 [161]3 years ago
8 0
The answer is b that’s the correct answer
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What is the solution to the system of linear equations? <br> {2x+4y=38 <br> 10x+3y=105
natali 33 [55]
This is the concept of simultaneous equations, the question requires us to solve the system of equations given by:
2x+4y=38
10x+3y=105
from the top equation;
2x=38-4y
dividing through by 2 we get:
x=19-2y......(*)
substituting (*) in the second equation we get:
10x+3y=105
10(19-2y)+3y=105
190-20y+3y=105
collecting like terms we get:
-20y+3y=105-190
-17y=-85
dividing both sides by -17 we get:
(-17y)/(-17)=(-85)/(-17)
y=5
thus
x=19-2y
x=19-2*5
x=19-10
x=9
thus
x=9 and y=5
8 0
3 years ago
Let g(x) = – x^2 + 4x + 3. Find and simplify g(-3).​
Evgen [1.6K]

Steps to solve:

g(x) = – x^2 + 4x + 3 when g(-3).

~Substitute x with -3.

g(-3) = -(-3)^2 + 4(-3) + 3

~Simplify

g(-3) = -9 - 12 + 3

~Simplify using PEMDAS

g(-3) = -18

Best of Luck!

7 0
3 years ago
Read 2 more answers
What do u add to 5/7/8 to make 8
Sedaia [141]

Answer: w hcel eblk lne nleem

Step-by-step explanation:

4 0
4 years ago
2(4+c)=67 help solve for c
vesna_86 [32]

Answer:

c = 29.5 or

c = 59/2

Step-by-step explanation:

2 (4 + c) = 67

8 + 2c = 67

8 - 8 + 2c = 67 - 8

2c = 59

c = 29.5

8 0
3 years ago
A researcher estimates the 90% CI for a sample with a mean of M = 8.9 and a standard error (sigma_M) of 2.1. What is the confide
Shalnov [3]

Answer:

The confidence interval at this level of confidence is between 5.4455 and 12.3545.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.9}{2} = 0.05

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.05 = 0.95, so z = 1.645

Now, find M as such

M = z*s

In which s is the standard deviation of the sample, which is also called standard error. So

M = 1.645*2.1 = 3.4545

The lower end of the interval is the sample mean subtracted by M. So it is 8.9 - 3.4545 = 5.4455

The upper end of the interval is the sample mean added to M. So it is 8.9 + 3.4545 = 12.3545

The confidence interval at this level of confidence is between 5.4455 and 12.3545.

4 0
4 years ago
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