Answer:
Both A and B
Step-by-step explanation:
For functions you are just trying to make sure all the x's are different.
So let's look at A: The x's there are all different so it is a function
Now let's look at B: The x's there are all different so it is a function.
Both A and B
Answer:
Step-by-step explanation:
6v + 12b = 504 eq1
2v + 5b = 204 eq2
6v + 15b = 612 eq2 times 3
0 -3b = 504 - 612 subtraction of the two bolded eqs
-3b = -108 solve for b
b = 36
Another way to solve the problem
6v + 12b = 504 I would eliminate the v term by multiplying the bottom
2v + 5b = 204 equation by -3 on BOTH sides and then add the two eqs
2v + 5b = 204
-3(2v + 5b) = -3(204)
-6v - 15b = -612
6v + 12b = 504
-6v - 15b = -612 add the like terms
(6v + (-6v)) + (12b + (-15b) = 504 + (-612)
(6v -6v)) + (12b - 15b) = 504 - 612)
0 + -3b = - 108 solve for b divide both sides by -3
b = -108/-3
b = 36
use eq 2v + 5b = 204 to solve for v and knowing b = 36
2v + 5b = 204 b=36
2v + 5(36) = 204 substract 5 times 36 from both sides
2v = 204 - 180
v = 24 / 2
v = 12
NOW CHECK the values for b and v using the OTHER eq
6v + 12b = 504
6(12) + 12(36) = 504
72 + 432 = 504
504 = 504 IT CHECKS
A solid line, because each lunch cost the same, and the price does not differ from lunch to lunch. So, 100 - 4 = 96 | 96 - 4 = 92, etc.
Option B:
sin x = 1 is the equation represented by the intersection of the graph.
Solution:
The graph lies between -1 and 1 in y-axis.
x-axis of the graph is all real numbers.
The graph oscillates between -1 and 1 and a shape that repeats itself every 2π units.
That is the domain of the graph is all real numbers.
The range of the graph is [-1, 1].
It clearly shows that, it is the graph of sinx = 1.
Hence sin x = 1 is the equation represented by the intersection of the graph.
Option B is the correct answer.
Answer:
The distribution is symmetrical.
Step-by-step explanation:
The box plot is symmetrical.
