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irina1246 [14]
4 years ago
12

A quadratic equation in form ax2 + bx + c = 0 cannot have:

Mathematics
2 answers:
Effectus [21]4 years ago
4 0
It might be D but i'm not really sure... 
sorry...
svetoff [14.1K]4 years ago
4 0

Answer:

b. one imaginary solution

Step-by-step explanation:

If there is an imaginary solution the second term is always +/- ci where c is a real constant

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Find the approximate solution of this system of equations. y=x^2+5x+3 y=square root2x+5
Anni [7]
We have that
y=x²<span>+5x+3
y=</span>√(<span>2x+5)

using a graph tool
see the attached figure

the solution is 
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y=2.156

therefore

the answer is the option
</span>B.) (-0.2, 2.1)

6 0
3 years ago
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Find the area of a triangle with a base length of 3 units and a height of 4 units.
svetlana [45]

Answer:

6 square units

Step-by-step explanation:

The area of a triangle can be calculated by multiplying the triangle's base by its height, and then dividing the result by 2. As an algebraic expression, this would be \frac{bh}{2}, where b is the triangle's base and h is the triangle's height. In this case, we know that b=3 and h=4. Therefore, the area of this triangle is \frac{3*4}{2} =\frac{12}{2} =6 square units. Hope this helps!

6 0
3 years ago
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What is the result when 12x} + 17x² + 18x + 9 is divided by 4x + 3?
melamori03 [73]

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17x^2+31x+3

Step-by-step explanation:

4 0
3 years ago
Solving by elimination <br> 5x+2y= -3<br> 3x+3y=9<br> please help me solve x and y
-Dominant- [34]
1) -3(5x+2y=-3)⇒ -15x-6y=9
                                             ⇒ -9x=27
     2(3x+3y=9)⇒ 6x+6y=18

2) -9x/-9=27/-9 ⇒ x=-3 

3) 3(-3)+3y=9⇒ -9+9+3y=9+9⇒ 3y/3=18/3⇒ y=6

Answer: (-3,6)

Reasoning:
Step 1) In order to eliminate, first I had to multiple the first equation by -3 and the second by 2 so that when combining the equations y would cancel each other out so that I could solve for x. <em>Note: There are many combinations as to how you could multiple the equations so that either the x or y would cancel out.
</em>
Step 2) Once y is eliminated, solve for x.

Step 3) Now plug x back into one of the original equations and solve for y. <em>Note: Plug x back into one of the original equations, not the equations that were changed by multiplication,</em> 

6 0
3 years ago
Q= QUADRADO
Lubov Fominskaja [6]
Answer
C x Q x T = ? = 24
6 0
3 years ago
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