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oksano4ka [1.4K]

3 years ago

7

The number of candies in the bag was less than 80. If it is possible to divide all the candies evenly among 3, 4, and 5 children

, how many candies were in the box?

2 answers:

Lelechka [254]3 years ago

6 0

Answer:

60 candies

Step-by-step explanation:

multiply 3 by 4 by 5 and you get 60, which has 3, 4, and 5 as prime factor, thus, making it possible to have an equal share with less than 80 candies

insens350 [35]3 years ago

4 0

60 candies

3*4*5=60

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evablogger [386]

${\huge{\boxed{\sf{Question}}$

$-1.2= y\div2.4 -1.7$

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${\huge{\boxed{\sf{Answer\:with\:explanation }}}$

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$-1.2= y\div2.4 -1.7$

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${\huge{\boxed{\sf{BOMDAS }}}$

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${\huge{\boxed{\sf{Solve\:the\:equation}}}$

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$y\div2.4-1.7=-1.2$

${\underline{simplify}}$

$0.416667y-1.7=-1.2$

add $1.7$ to both sides

$0.416667y=0.5$

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${\huge{\boxed{\sf{Answer}}}$

$y$ would equal $1.2$

4 0

2 years ago

Translate into an algebraic expression: n−1 increased by 110%

lorasvet [3.4K]

Answer:

Part 1) The algebraic expression is equal to $1.10(n-1)$ or $1.10n-1.10$

Part 2) The algebraic expression is equal to $\frac{1.10}{n}$

Step-by-step explanation:

Part 1) we have (n-1) increased by 110%

110%=110/100=1.10

so

The algebraic expression of (n-1) increased by 110% is equal to multiply 1.10 by (n-1)

$1.10(n-1)$

Distributed

$1.10n-1.10$

Part 2) we have n^(-1) increased by 110%

110%=110/100=1.10

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The algebraic expression of n^(-1) increased by 110% is equal to multiply 1.10 by n^(-1)

Remember that

$n^{-1}=\frac{1}{n}$

so

$1.10(n^{-1})=1.10\frac{1}{n}=\frac{1.10}{n}$

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3 years ago

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deff fn [24]

8:15 or 8 to 15 would be the ratio because you compare 8 quarters to 15 coins.

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3 years ago

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adell [148]

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