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2 years ago

Given the graphed function below, which of the following ordered pairs are

Mathematics

2 answers:

Paul [167]2 years ago

7 0

Answer:

Step-by-step explanation:

On the inverse, you switch the x and y. So on the function there is point (-2,-11) and on the inverse there is point (-11,-2)

kondor19780726 [428]2 years ago

3 0

Answer:

Step-by-step explanation:

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You are hiring a limousine. One company charges a $60 reservation fee plus another $15 per hour. A second company charges a $25

anzhelika [568]

Answer:

7 hours

Step-by-step explanation:

Step one:

given data

let the total charges be y and the number of hours be x

Company A charges

$60 reservation fee plus another $15 per hour.

y=60+15x----------1

Company B charges

$25 reservation fee plus another $20 per hour

y=25+20x------------2

Step two:

equate the 2 expressions above we have

60+15x=25+20x

collect like terms

60-25=20x-15x

35=5x

divide both sides by 5

x= 35/5

x= 7 hours

5 0

2 years ago

I NEED HELP ASAP I WILL GIVE ALL MY POINTS AWAY FOR THIS

podryga [215]

Step-by-step explanation: the tangent is 8/6 because it is the opposite (8) over the adjacent (6)

8 0

2 years ago

In downtown Charlotte, building inspectors must regulate the height of buildings. From the top of the BB&T building which is

Morgarella [4.7K]

Answer:

296.89 m

Step-by-step explanation:

assuming that both the buildings are on level ground (i.e their bases are at the same elevation), see attached.

5 0

2 years ago

What is the value of x?<br> *36<br> *72<br> *108<br> *144

Anit [1.1K]

Answer:

Step-by-step explanation:

6 0

1 year ago

Find an equation of the tangent line to the hyperbola y = 3/x at the point (3, 1).

Vesna [10]

Let's find the derivative of that hyperbola in order to find a slope formula to help us with this equation. We already have an x and y value. The derivative is found this way: $y'= \frac{x(0)-3(1)}{x^2}$ so $y'=- \frac{3}{x^2}$ . The derivative supplies us with the slope formula we need to write the equation. Sub in the x value of 3 to find what the slope is: $y'=- \frac{3}{3^2}=- \frac{3}{9}=- \frac{1}{3}$ . So in our slope-intercept equation, x = 3, y = 1, and m = -1/3. Use these values to solve for b. $1=- \frac{1}{3}(3)+b$ so b = 2. The equation, then, for the line tangent to that hyperbola at that given point is $y=- \frac{1}{3}x+2$

6 0

3 years ago