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Amanda [17]
3 years ago
11

4x-6y-8=0 in function form

Mathematics
1 answer:
gizmo_the_mogwai [7]3 years ago
6 0
If you are solving for Y the answer is Y= 2/3x - 4/3
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The exchange rate is £1 =$1.54 how many $ would I get for £200
Andreyy89
Let's see, if 1 pound = $1.54, let's times 1.54 by 200, the answer is $308, hope this helps
3 0
3 years ago
Please help me with this math problem <br>Evaluate C/2 - 3 + 6/D when c=14 and d=3
lbvjy [14]

\frac{c}{2}  - 3 +  \frac{6}{d }  =  \\  =  \frac{14}{2}  - 3 +  \frac{6}{3}  =  \\  = 7 - 3 + 2 =  \\ =  6
7 0
4 years ago
Read 2 more answers
h(x)= \dfrac{1}{8} x^3 - x^2h(x)= 8 1 ​ x 3 −x 2 h, left parenthesis, x, right parenthesis, equals, start fraction, 1, divided b
Nesterboy [21]

Answer:

\dfrac{1}{2}

Step-by-step explanation:

Given the function h(x)=\dfrac{1}{8}x^3-x^2

The average rate of change of the function h(x) over the interval a\le x\le b can be calculated using formula

\dfrac{h(b)-h(a)}{b-a}

In your case,

a=-2,\\ \\b=2,

so the average rate of change is

\dfrac{h(2)-h(-2)}{2-(-2)}\\ \\=\dfrac{(\frac{1}{8}\cdot 2^3-2^2)-(\frac{1}{8}\cdot (-2)^3-(-2)^2)}{4}\\ \\=\dfrac{(1-4)-(-1-4)}{4}\\ \\=\dfrac{-3+5}{4}\\ \\=\dfrac{2}{4}\\ \\=\dfrac{1}{2}

6 0
3 years ago
Someone help me ! Please
zzz [600]

Answer:

the answer would be B

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Find an equation of the sphere with center (4, −12, 8) and radius 10. use an equation to describe its intersection with each of
xxMikexx [17]
<span>Sphere: (x - 4)^2 + (y + 12)^2 + (z - 8)^2 = 100 Intersection in xy-plane: (x - 4)^2 + (y + 12)^2 = 36 Intersection in xz-plane: DNE Intersection in yz-plane: (y + 12)^2 + (z - 8)^2 = 84 The desired equation is quite simple. Let's first create an equation for the sphere centered at the origin: x^2 + y^2 + z^2 = 10^2 Now let's translate that sphere to the desired center (4, -12, 8). To do that, just subtract the center coordinate from the x, y, and z variables. So (x - 4)^2 + (y - -12)^2 + (z - 8)^2 = 10^2 (x - 4)^2 + (y - -12)^2 + (z - 8)^2 = 100 Might as well deal with that double negative for y, so (x - 4)^2 + (y + 12)^2 + (z - 8)^2 = 100 And we have the desired equation. Now for dealing with the coordinate planes. Basically, for each coordinate plane, simply set the coordinate value to 0 for the axis that's not in the desired plane. So for the xy-plane, set the z value to 0 and simplify. So let's do that for each plane: xy-plane: (x - 4)^2 + (y + 12)^2 + (z - 8)^2 = 100 (x - 4)^2 + (y + 12)^2 + (0 - 8)^2 = 100 (x - 4)^2 + (y + 12)^2 + (-8)^2 = 100 (x - 4)^2 + (y + 12)^2 + 64 = 100 (x - 4)^2 + (y + 12)^2 = 36 xz-plane: (x - 4)^2 + (y + 12)^2 + (z - 8)^2 = 100 (x - 4)^2 + (0 + 12)^2 + (z - 8)^2 = 100 (x - 4)^2 + 12^2 + (z - 8)^2 = 100 (x - 4)^2 + 144 + (z - 8)^2 = 100 (x - 4)^2 + (z - 8)^2 = -44 And since there's no possible way to ever get a sum of 2 squares to be equal to a negative number, the answer to this intersection is DNE. This shouldn't be a surprise since the center point is 12 units from this plane and the sphere has a radius of only 10 units. yz-plane: (x - 4)^2 + (y + 12)^2 + (z - 8)^2 = 100 (0 - 4)^2 + (y + 12)^2 + (z - 8)^2 = 100 (-4)^2 + (y + 12)^2 + (z - 8)^2 = 100 16 + (y + 12)^2 + (z - 8)^2 = 100 (y + 12)^2 + (z - 8)^2 = 84</span>
6 0
3 years ago
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