your friend's house is 7.5 miles north and 10 miles west of the zoo. How far is your friend's house from the zoo?

Mathematics

1 answer:

maria [59]2 years ago

3 0

Answer:

2.5 miles

Step-by-step explanation:

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Have you ever been on or seen a ride like this at a fair or amusement park? Imagine being strapped into your seat at the bottom

Montano1993 [528]

Answer:

Step-by-step explanation:

The only question here seems to be ...

Have you ever been on or seen a ride like this at a fair or amusement park?

I have not seen such a ride.

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2 years ago

981 rounded to nearest 100

sergey [27]

Answer: 1000

Step-by-step explanation:

9 8 1

Hundred tens one

The question is asking for to round to the nearest hundred (100) which means is rounding to [9] in this question.

The number of the place before the hundreds place is [8] on the tens place.

When numbers are greater than or equal to 5, you round up a digit.
When numbers are less than 5, you round down a digit.

[8] is greater than 5, so you round 9 up. When rounding 9 up, you get 10.

<h2>So, the final number will be 1000</h2>

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3 years ago

Jonah has a recipe that uses 1 1/2 cups of brown sugar and 2 1/3 cups of flour. Jonah wants to use all of his flour to make as m

S_A_V [24]

Answer:

4 1/2

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

39-50 find the limit. 41. <img src="https://tex.z-dn.net/?f=%5Clim%20_%7Bt%20%5Crightarrow%200%7D%20%5Cfrac%7B%5Ctan%206%20t

Katyanochek1 [597]

Write tan in terms of sin and cos.

$\displaystyle \lim_{t\to0}\frac{\tan(6t)}{\sin(2t)} = \lim_{t\to0}\frac{\sin(6t)}{\sin(2t)\cos(6t)}$

Recall that

$\displaystyle \lim_{x\to0}\frac{\sin(x)}x = 1$

Rewrite and expand the given limand as the product

$\displaystyle \lim_{t\to0}\frac{\sin(6t)}{\sin(2t)\cos(6t)} = \lim_{t\to0} \frac{\sin(6t)}{6t} \times \frac{2t}{\sin(2t)} \times \frac{6t}{2t\cos(6t)} \\\\ = \left(\lim_{t\to0} \frac{\sin(6t)}{6t}\right) \times \left(\lim_{t\to0}\frac{2t}{\sin(2t)}\right) \times \left(\lim_{t\to0}\frac{3}{\cos(6t)}\right)$

Then using the known limit above, it follows that

$\displaystyle \left(\lim_{t\to0} \frac{\sin(6t)}{6t}\right) \times \left(\lim_{t\to0}\frac{2t}{\sin(2t)}\right) \times \left(\lim_{t\to0}\frac{3}{\cos(6t)}\right) = 1 \times 1 \times \frac3{\cos(0)} = \boxed{3}$