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fomenos
3 years ago
9

Pls answer this for me, this is the remainder theorem for grade 9 so help me.

Mathematics
2 answers:
GrogVix [38]3 years ago
8 0

Answer:

Step-by-step explanation:

1) x + 1 = 0

x = -1

P(x) = x³ + 5x² + 2x + 1

P(-1) = (-1)³ + 5(-1)² + 2*(-1) + 1

       = -1 + 5*1  -2 +1

       = - 1 +5 - 2 +1

P(-1) = 3

2)x -5 =0

x = 5

P(x) = x³ - 6x² + 5x + 2

P(5) =5³ -6*(5)²  + 5*5 + 2

    = 125 - 6*25 + 25 + 2

   = 125 - 150 + 25 +2

  P(5) = 2

professor190 [17]3 years ago
5 0

Answer:

1.  3

2. 2

Step-by-step explanation:

| |  

x | + | 1 | | x^2 | + | 4 x | - | 2

x^3 | + | 5 x^2 | + | 2 x | + | 1

x^3 | + | x^2 | | | |  

| | 4 x^2 | + | 2 x | |  

| | 4 x^2 | + | 4 x | |  

| | | | -2 x | + | 1

| | | | -2 x | - | 2

| | | | | | 3

__________________________________________

| |  

x | - | 5 | | x^2 | - | x | + | 0

x^3 | - | 6 x^2 | + | 5 x | + | 2

x^3 | - | 5 x^2 | | | |  

| | -x^2 | + | 5 x | |  

| | -x^2 | + | 5 x | |  

| | | | | | 2

| | | | | | 0

| | | | | | 2

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What is 6 squared ÷2(3)+4
julsineya [31]
6^{2} /2*3 +4 \\ 36/2*3+4 \\ 18*3+4 \\ 54+4 \\ 58
Hope this helps!
7 0
4 years ago
Find the value of n<br><br> 3n-10<br> n=
Mars2501 [29]

10-3=N

N=7

Step-by-step explanation:

hope you like it

8 0
3 years ago
Read 2 more answers
Can you help me with this? Thank you.
Rudik [331]

Answer:

1464

Step-by-step explanation:

(110-85)/2 * (85+110)/2 + (((110-85)/2)^2*pi)/2 using Calculus lvl 5.6

thus getting 1464 rounded

4 0
3 years ago
Drag each equation to the correct location on the table. Classify each function as linear or nonlinear.
drek231 [11]

Answer:

B and f

Step-by-step explanation:

Because I did the work

8 0
3 years ago
How many ways are there to assign six jobs to five different employees if every employee is assigned at least one job?
NARA [144]

Answer:

There are 1800 different ways.

Step-by-step explanation:

A permutation give as the total ways in which we can organized a group of elements where the order is important. So, the  permutation of n elements when all of them are not different is calculate as:

\frac{n!}{n1!n2!...nk!}

Where k is the number of elements that are different, n1, n2, ... nk are the number of times that very element appears and n is equal to n1+n2+...nk.

In this case we have 5 differents and general ways to assign six jobs to five different employees:

1. the first employee receive 2 jobs

2. the second employee receive 2 jobs

3. the third employee receive 2 jobs

4. the fourth employee receive 2 jobs

5. the fifth employee receive 2 jobs

Then, if the first employe receive 2 jobs, its mean that we have six people to permutate and the first person appears two times.

So the permutation of this 6 element in which one is repeat 2 times is calculate as:

\frac{6!}{2!*1!*1!*1!*1!*1!}=360

Therefore, there are 360 ways to organized five different employees into 6 jobs where the first person can receive two jobs.

For the other 4 options we can made the same calculation, so the total number of ways that we can organized five employees in six jobs are calculate as:

360*5=1800

Finally there are 1800 different ways.

3 0
3 years ago
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