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castortr0y [4]
4 years ago
6

Is writing an equation this way ( 4 x 5 )-9-6 correct? If not why?

Mathematics
1 answer:
Soloha48 [4]4 years ago
6 0
No, it is not correct. There is no equal sign, so the expression is not an equation.
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3. Solve the equation for y.<br> 3(2y + 4) = 8y<br><br> A. –8<br> B. –6<br> C. –2<br> D. 2<br> E. 6
AfilCa [17]

Answer:

y = 6

Step-by-step explanation:

Perform the indicated multiplication:  6y + 12 = 8y

Consolidate y terms on the right:                12 = 8y - 6y = 2y, or y = 6

7 0
3 years ago
Which data set could be represented by the box plot shown below?
Step2247 [10]

Answer:

  (D)

Step-by-step explanation:

The box plot is a visual representation of the 5-number summary of the data. It shows the extremes, the quartiles and the median.

__

Each data set has 11 elements, sorted into increasing order.

<h3>extremes</h3>

The first and last elements of the data set correspond to the ends of the whiskers, so you are looking for a set that ranges from 3 to 18. (This eliminates choice B.)

<h3>median</h3>

The median will be the middle element, the 6th from either end. The vertical line in the box identifies its value as 10. (This eliminates choice A.)

<h3>quartiles</h3>

The first quartile is the middle element of the bottom half of the data set (what remains after the median and above elements are removed). There are 5 elements in the bottom half, so the first quartile is the 3rd one. It is signified by the left end of the box in the box plot. Its value is 7. (This eliminates choice C.)

Similarly, the third quartile is the 3rd element from the right end of the data set. The value 13 in choice D matches the right end of the box in the box plot.

The box plot represents the data set in Choice D.

8 0
2 years ago
Relative density was determined for one sample of second-growth Douglas fir 2 x 3 4s with a low percentage of juvenile wood and
Citrus2011 [14]

Answer:

0.03865

Step-by-step explanation:

Since the true density for the two types of trees are given, we would evaluate the average for both of them

Low percentage of juvenile wood density = 0.523 and 0.0543

Average density = 0.523 + 0.0543/2

Average density = 0.55015

Moderate percentage of juvenile wood density = 0.489 and 0.0450

Average density = 0.489 + 0.0450/2

Average density = 0.5115

Therefore, difference in true average density for the two woods are = 0.55015 - 0.51150

= 0.03865

5 0
3 years ago
A farmer wants to build a rectangular garden 10ft long and 6ft wide. How many feet of fencing should he buy?
Lana71 [14]
He should buy 32 feet of fencing. I got 32 by just finding the perimeter or in other words adding 10+10+6+6 which equal 32. You would NOT do area or 10×6 because that would include that land within the fenced area and who wants 60 feet of fencing that you can't put anything in?

Good luck, hope that helped.
6 0
3 years ago
Heeeeeeeelp!!!!!!!!!!!
Natasha_Volkova [10]
A is the answer because if you calculate the answer correctly. that will be so.
8 0
4 years ago
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