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jarptica [38.1K]
4 years ago
15

Relative density was determined for one sample of second-growth Douglas fir 2 x 3 4s with a low percentage of juvenile wood and

another sample with a moderate percentage of juvenile wood, resulting in the following data
Type n x s
Low 35 0.523 0.0543
Moderate 54 0.489 0.0450

Estimate the difference between true average density for the two types of wood.
Mathematics
1 answer:
Citrus2011 [14]4 years ago
5 0

Answer:

0.03865

Step-by-step explanation:

Since the true density for the two types of trees are given, we would evaluate the average for both of them

Low percentage of juvenile wood density = 0.523 and 0.0543

Average density = 0.523 + 0.0543/2

Average density = 0.55015

Moderate percentage of juvenile wood density = 0.489 and 0.0450

Average density = 0.489 + 0.0450/2

Average density = 0.5115

Therefore, difference in true average density for the two woods are = 0.55015 - 0.51150

= 0.03865

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Answer:

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he rigth equation to anticipate the profit after t years is p(t) = 10,000 (1.075)^t

So, given that both

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=> pA(t) / pB(t') = 1.075^t / 1.075^t'

=> pA(t) / pB(t') = 1.075 ^ (t - t')

And t - t' = 0.5 years

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=> pB(t') ≈ 0.96 * pA(t)

This means that the profit of store B is about 96%of  the profit of store A at any time after both stores have opened.

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2 years ago
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V125BC [204]

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Step-by-step explanation:

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Shkiper50 [21]

Answer:

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Step-by-step explanation:

<h3>Given</h3>
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<h3>To find </h3>
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