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Evgen [1.6K]
3 years ago
5

AC is the diameter. Calculate the area of the sector (to the nearest whole number) created by ∠CDB.

Mathematics
1 answer:
TiliK225 [7]3 years ago
3 0

Area of the circle is πr² which corresponds to an angle of 360° subtended at the center. Thus, the area of a sector subtending angle \theta at the centre is:

Area= \frac{\theta}{360}\times \pi r^2

In this case put $\theta$ equal to 30°

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Answer:

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Step-by-step explanation:

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Simplify

3

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8 0
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Please help thanks :)
Igoryamba
Y = -1/2x + 5 is the answer
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A city employee collected survey data from 2330 randomly selected residents. A total of 865 of these residents said that they th
timurjin [86]
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A cone with a height of 15 yards has a volume of 475.17 yd^3 find the diameter of the cone
solniwko [45]

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8 0
3 years ago
The perimeter of a rectangle is represented by
MissTica

The perimeter of a rectangle is represented by 4x^2 + 5x − 2. The perimeter of a smaller rectangle is represented by x^2 + 3x + 5. Which polynomial expression BEST represents how much larger the first rectangle is than the smaller rectangle?

A) 3x^2 + 2x − 7

B) 3x^2 + 2x − 3

C) 3x^2 + 8x + 3

D) 5x^2 + 8x − 7

<h3><u>Answer:</u></h3>

Option A

The polynomial expression best represents how much larger the first rectangle is than the smaller rectangle is 3 x^{2}+2 x-7

<h3><u>Solution:</u></h3>

Perimeter of a rectangle is represented by 4x^2 + 5x − 2

Perimeter of a smaller rectangle is represented by x^2 + 3x + 5

To Find : Polynomial expression that represents how much larger the first rectangle is than the smaller rectangle.

Which means we have to find difference between perimeter of both rectangles

Subtract the equation of perimeter of  smaller rectangle from equation of  perimeter of a larger rectangle

Difference = perimeter of a larger rectangle - perimeter of  smaller rectangle

\text {Difference }=\left(4 x^{2}+5 x-2\right)-\left(x^{2}+3 x+5\right)

On removing the brackets we get,

\begin{array}{l}{\text { Difference }=4 x^{2}+5 x-2-x^{2}-3 x-5} \\\\ {\text { Difference }=3 x^{2}+2 x-7}\end{array}

Thus option A is correct

8 0
3 years ago
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