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Pavel [41]
3 years ago
14

△FSB∼△ZDR . What is the value of x? Enter your answer. How many units?

Mathematics
1 answer:
kari74 [83]3 years ago
4 0
Answer: 22

---------------------------------------------------------

Explanation:

The triangles are similar, so we know the corresponding sides form ratios that are equal. 

Note how...
FS and ZD are the first two letters of FSB and ZDR respectively
FB and ZR are the first & last letters of FSB and ZDR respectively

Based on those two facts above, we can form this proportion
FS/ZD = FB/ZR
38/15.2 = 55/x

Solve for x
38/15.2 = 55/x
38*x = 15.2*55
38*x = 836
x = 836/38
x = 22

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Can someone help me?
soldier1979 [14.2K]

Answer:

Step-by-step explanation:

First your going to plug in what p and q are into the equation so 3(2)^5+10(-3)^2 over 7(2)+1.

Your going to first do (2)^5 and (-3)^2 so it’s going to be 3(32)+10(9) over (multiply the 7(2) first) 14+1.

3(32)+10(9) over 14+1 now multiply 3(32) and 10(9) you should get (96)+(90) over 15.

add 96+90 to get 186 over 15.

then divide how many times 15 can go into 186 you should get 12 6/15 and divide 6/15 by 3 to get your final answer 12 2/5.

I hope this helps!

5 0
2 years ago
Consider the given function and the given interval. f\(x\) = (x - 7)**2 text(, ) [5 text(, ) 11] (a) Find the average value fave
Jet001 [13]

a. f has an average value on [5, 11] of

f_{\rm ave}=\displaystyle\frac1{11-5}\int_5^{11}(x-7)^2\,\mathrm dx=\frac{(x-7)^3}{18}\bigg|_5^{11}=\frac{4^3-(-2)^3}{18}=4

b. The mean value theorem guarantees the existence of c\in(5,11) such that f(c)=f_{\rm ave}. This happens for

(c-7)^2=4\implies c-7=\pm2\implies c=9\text{ or }c=5

8 0
3 years ago
The length of a picture frame is 7 inches more than the width. For what values of x is the perimeter of the picture frame greate
makkiz [27]
P=2(L+W)
l=x+7
w=x
P=2(x+7+x)
P=2(2x+7)
P=4x+14

hast to be greater than 154

P>154
4x+14>154
minus 14 both sides
4x>140
divide 4
x>35


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the answer is0.0101010101
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