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3 years ago

Can someone help me?

Mathematics

1 answer:

soldier1979 [14.2K]3 years ago

5 0

Answer:

Step-by-step explanation:

First your going to plug in what p and q are into the equation so 3(2)^5+10(-3)^2 over 7(2)+1.

Your going to first do (2)^5 and (-3)^2 so it’s going to be 3(32)+10(9) over (multiply the 7(2) first) 14+1.

3(32)+10(9) over 14+1 now multiply 3(32) and 10(9) you should get (96)+(90) over 15.

add 96+90 to get 186 over 15.

then divide how many times 15 can go into 186 you should get 12 6/15 and divide 6/15 by 3 to get your final answer 12 2/5.

I hope this helps!

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−6p=48<br><br> Help a kid out

Semenov [28]

Answer:

p = -8

Step-by-step explanation:

-6p = 48

divide both sides by -6

p = -8

5 0

3 years ago

Jane must get at least three of the four problems on the exam correct to get an A. She has been able to do 80% of the problems o

NISA [10]

Answer:

a) There is n 81.92% probability that she gets an A.

b) If she gets the first problem correct, there is an 89.6% probability that she gets an A.

Step-by-step explanation:

For each question, there are only two possible outcomes. Either the answer is correct, or it is not. This means that we can solve this problem using binomial distribution probability concepts.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And $\pi$ is the probability of X happening.

For this problem, we have that:

The probability she gets any problem correct is 0.8, so $\pi = 0.8$ .

(a) What is the probability she gets an A?

There are four problems, so $n = 4$

Jane must get at least three of the four problems on the exam correct to get an A.

So, we need to find $P(X \geq 3)$

$P(X \geq 3) = P(X = 3) + P(X = 4)$

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

$P(X = 3) = C_{4,3}.(0.80)^{3}.(0.2)^{1} = 0.4096$

$P(X = 4) = C_{4,4}.(0.80)^{4}.(0.2)^{0} = 0.4096$

$P(X \geq 3) = P(X = 3) + P(X = 4) = 2*0.4096 = 0.8192$

There is n 81.92% probability that she gets an A.

(b) If she gets the first problem correct, what is the probability she gets an A?

Now, there are only 3 problems left, so $n = 3$

To get an A, she must get at least 2 of them right, since one(the first one) she has already got it correct.

So, we need to find $P(X \geq 2)$

$P(X \geq 3) = P(X = 2) + P(X = 3)$

$P(X = 2) = C_{3,2}.(0.80)^{2}.(0.2)^{1} = 0.384$

$P(X = 4) = C_{3,3}.(0.80)^{3}.(0.2)^{0} = 0.512$

$P(X \geq 3) = P(X = 2) + P(X = 3) = 0.384 + 0.512 = 0.896$

If she gets the first problem correct, there is an 89.6% probability that she gets an A.

3 0

3 years ago

Please help me!<br> [One Step Inequalities]

WITCHER [35]

n - 8 < -8

< is similar to = in this case

n < -8 + 8
n < 3

The answer would be bubble #3.

7 0

2 years ago

Find the point on the line y = 2x +1 that is closest to the point (5, 2).

ELEN [110]

I believe that it's (1,3)
(tip: with these problems, try to use desmos.com)

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3 years ago

S the following sentence true or false? If no desk or table is available, you should crouch against an outside wall.

Flura [38]

Answer:

1st- what scenario are talking about?

2nd- false, becuase if you hide under any objects there is the risk of it falling over you and hurting you

7 0

3 years ago