All categories

2 years ago

Can someone help me?

Mathematics

1 answer:

soldier1979 [14.2K]2 years ago

5 0

Answer:

Step-by-step explanation:

First your going to plug in what p and q are into the equation so 3(2)^5+10(-3)^2 over 7(2)+1.

Your going to first do (2)^5 and (-3)^2 so it’s going to be 3(32)+10(9) over (multiply the 7(2) first) 14+1.

3(32)+10(9) over 14+1 now multiply 3(32) and 10(9) you should get (96)+(90) over 15.

add 96+90 to get 186 over 15.

then divide how many times 15 can go into 186 you should get 12 6/15 and divide 6/15 by 3 to get your final answer 12 2/5.

I hope this helps!

You might be interested in

Use the quadratic formula to determine the exact solutions to the equation 6x^2 + 4x - 3 = 0

mezya [45]

To solve quadratics, the most correct and effective way, in my opinion, is the quadratic formula:

$x={\frac {-b\pm {\sqrt {b^{2}-4ac}}}{2a}}.$ 

Plugging it in, we get:

 $\frac{-4\pm \sqrt{16+72} }{12} = \frac{-4\pm 2\sqrt{22}}{12} = \frac{-2\pm \sqrt{22} }{6}$

So the final answer is:

$\frac{ \sqrt{22}-2 }{6}$ and $\frac{-2- \sqrt{22} }{6}$

5 0

3 years ago

Someone pleasee help i only have less then 12 min to submit (::

Lina20 [59]

Answer: A and B are the legs and C is the hypotenuse

8 0

3 years ago

Solve each inequality, and then drag the correct solution graph to the inequality.

Nesterboy [21]

The correct solution graph to the inequalities are

$4(9x-18)>3(8x+12)$ → C

$-\frac{1}{3}(12x+6) \geq -2x +14$ → A

$1.6(x+8)\geq 38.4$ → B

(NOTE: The graphs are labelled A, B and C from left to right)

For the first inequality,

$4(9x-18)>3(8x+12)$

First, clear the brackets,

$36x-72>24x+36$

Then, collect like terms

$36x-24x>36+72\\12x >108$

Now divide both sides by 12

$\frac{12x}{12} > \frac{108}{12}$

∴ $x > 9$

For the second inequality

$-\frac{1}{3}(12x+6) \geq -2x +14$

First, clear the fraction by multiplying both sides by 3

$3 \times[-\frac{1}{3}(12x+6)] \geq3 \times( -2x +14)$

$-1(12x+6) \geq -6x +42$

Now, open the bracket

$-12x-6 \geq -6x +42$

Collect like terms

$-6 -42\geq -6x +12x$

$-48\geq 6x$

Divide both sides by 6

$\frac{-48}{6} \geq \frac{6x}{6}$

$-8\geq x$

∴ $x\leq -8$

For the third inequality,

$1.6(x+8)\geq 38.4$

First, clear the brackets

$1.6x + 12.8\geq 38.4$

Collect likes terms

$1.6x \geq 38.4-12.8$

$1.6x \geq 25.6$

Divide both sides by 1.6

$\frac{1.6x}{1.6}\geq \frac{25.6}{1.6}$

∴ $x \geq 16$

Let the graphs be A, B and C from left to right

The first graph (A) shows $x\leq -8$ and this matches the 2nd inequality

The second graph (B) shows $x \geq 16$ and this matches the 3rd inequality

The third graph (C) shows $x > 9$ and this matches the 1st inequality

Hence, the correct solution graph to the inequalities are

$4(9x-18)>3(8x+12)$ → C

$-\frac{1}{3}(12x+6) \geq -2x +14$ → A

$1.6(x+8)\geq 38.4$ → B

Learn more here: brainly.com/question/17448505

8 0

2 years ago

An equation that represents the path of a diver jumping off a diving board is y = –7x2 + 5x + 16. Graph this function from the p

ANTONII [103]

Answer:

See explanation

Step-by-step explanation:

An equation that represents the path of a diver jumping off a diving board is

$y = -7x^2 + 5x + 16.$

The diver jumped to the water when x = 0.

Then

$y=-7\cdot 0^2+5\cdot 0+16=16$

The jumper reached the water when y = 0, then

$-7x^2+5x+16=0\\ \\D=5^2-4\cdot (-7)\cdot 16=25+448=473\\ \\x_{1,2}=\dfrac{-5\pm\sqrt{473}}{-14}$

So, point where the jumper reached the water is

$\left(\dfrac{5+\sqrt{473}}{14},0\right)\approx (1.93,0)$

7 0

3 years ago

Answer correctly

lara31 [8.8K]

6w-10 represents the total amount of fence will need to complete the rectangle of fence in his yard. The fence will need two lengths and 2 widths to complete the rectangle. If the width is w, and the length is 2w-5, then the total for the rectangle would be w+w+2w-5+2w-5 which simplifies to 6w-10.

7 0

3 years ago

Read 2 more answers