Answer:
6 Dollars.
Step-by-step explanation:
A toolset sells for $150 at a local hardware store. The toolset is on sale for 20% off the retail price, p, given by f(p) = 0.80p. Devon is interested in buying the toolset and has a coupon for $30 off the price of the toolset, which can be represented by g(p) = p – 30.
Therefore, the cost of using the coupon followed by the discount,
f[g(p)] = 0.80(p - 30) = 0.80(150 - 30) = 96 dollars.
And the cost of using the discount followed by the application of the coupon,
g[f(p)] = 0.80p - 30 = 0.80 × 150 - 30 = 90 dollars.
Therefore, the difference between f[g(p)] and g[f(p)] is (96 - 90 ) = 6 dollars. (Answer)
The radius is 5 so you can add 5 to the y value of the center to get (3,8)
Use the chain rule:
<em>y</em> = tan(<em>x</em> ² - 5<em>x</em> + 6)
<em>y'</em> = sec²(<em>x</em> ² - 5<em>x</em> + 6) × (<em>x</em> ² - 5<em>x</em> + 6)'
<em>y'</em> = (2<em>x</em> - 5) sec²(<em>x</em> ² - 5<em>x</em> + 6)
Perhaps more explicitly: let <em>u(x)</em> = <em>x</em> ² - 5<em>x</em> + 6, so that
<em>y(x)</em> = tan(<em>x</em> ² - 5<em>x</em> + 6) → <em>y(u(x))</em> = tan(<em>u(x)</em> )
By the chain rule,
<em>y'(x)</em> = <em>y'(u(x))</em> × <em>u'(x)</em>
and we have
<em>y(u)</em> = tan(<em>u</em>) → <em>y'(u)</em> = sec²(<em>u</em>)
<em>u(x)</em> = <em>x</em> ² - 5<em>x</em> + 6 → <em>u'(x)</em> = 2<em>x</em> - 5
Then
<em>y'(x)</em> = (2<em>x</em> - 5) sec²(<em>u</em>)
or
<em>y'(x)</em> = (2<em>x</em> - 5) sec²(<em>x</em> ² - 5<em>x</em> + 6)
as we found earlier.
Explanation: 750/30=25
The area is 30cm by 25cm because they multiply to 750
The answer would be 40x+0.30y
