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2 years ago

2 1/3 divided by 4/5

Mathematics

2 answers:

Law Incorporation [45]2 years ago

8 0

Answer:

(2 1/3) : (4/5) = 35 /12 = 2 11 /12

1. You convert the mixed number (2 1/3) into an improper fraction which is 7/3.

2.Then you find a new numerator so you multiply the whole number (2) by the denominator (3) which is 6.

3 Add the answer (6) to the starting numerator (1). The new numerator equation: 6+1=7.

4.Write the new numerator (7) over the denominator (3)

Two and one seven third is seven thirds.

5. Then you divide: 7/3 : 4/5 = 7/3 * 5/4 = 7*5/ 3*4

6. Multiply (7 and 5) and (3 and 4) which gives you 35/12.

7.Then you transform it back into a mixed number by dividing 35/12 which gives you 2 11/12.

irina [24]2 years ago

6 0

Answer: 2.91666666667

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1 year ago

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3 years ago

Given the set of vertices, determine whether parallelogram ABCD is a rhombus, rectangle or square. List all that apply. A(7,-4),

Sloan [31]

Given:

Vertices of a parallelogram ABCD are A(7,-4), B(-1,-4), C(-1,-12), D(7, -12).

To find:

Whether the parallelogram ABCD is a rhombus, rectangle or square.

Solution:

Distance formula:

$D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Using distance formula, we get

$AB=\sqrt{(-4-(-4))^2+(-1-7)^2}$

$AB=\sqrt{(-4+4)^2+(-8)^2}$

$AB=\sqrt{0+64}$

$AB=8$

Similarly,

$BC=\sqrt{(-1-(-1))^2+(12-(-4))^2}=8$

$CD=\sqrt{(7-(-1))^2+(-12-(-12))^2}=8$

$AD=\sqrt{(7-7)^2+(-12-(-4))^2}=8$

All sides of parallelogram are equal.

$AC=\sqrt{(-1-7)^2+(-12-(-4))^2}=8\sqrt{2}$

$BD=\sqrt{(7-(-1))^2+(-12-(-4))^2}=8\sqrt{2}$

Both diagonals are equal.

Since, all sides are equal and both diagonals are equal, therefore, the parallelogram ABCD is a square.

We know that, a square is special case of rectangles and rhombus.

So, parallelogram ABCD is a rhombus, rectangle or square. Therefore, the correct option is c.

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Answer:

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