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NeX [460]
3 years ago
7

Solve the following equation using the quadratic formula

Mathematics
1 answer:
Anarel [89]3 years ago
7 0

Answer:

A

Step-by-step explanation:

The quadratic formula is x=\frac{-b+/-\sqrt{b^2-4ac} }{2a}. Here a=1, b=-8, and c=97.

Substitute and you'll have:

x=\frac{-b+/-\sqrt{b^2-4ac} }{2a} =\frac{8+/-\sqrt{-8^2-4(1)(97)} }{2(1)}=\frac{8+/-\sqrt{64-388} }{2)}

\frac{8+/-\sqrt{-324} }{2}=\frac{8+/-18i }{2}=4+/- 9i

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Answer:

2 2/9

Step-by-step explanation:

4 0
2 years ago
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A random sample of 102 full-grown lobsters had a mean weight of 16 ounces and a standard deviation of 3.4 ounces. Construct a 98
pshichka [43]

Answer:

The best point estimate for a confidence interval estimating the population μ is 16 ounces.

The 98 percent confidence interval for the population mean μ is between 15.21 ounces and 16.79 ounces.

Step-by-step explanation:

We have the standard deviation for the sample, so we use the t-distribution to solve this question.

The best point estimate for a confidence interval estimating the population μ is

The sample mean, so 16 ounces.

T interval

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 102 - 1 = 101

98% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 101 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.98}{2} = 0.99. So we have T = 2.36

The margin of error is:

M = T\frac{s}{\sqrt{n}} = 2.36\frac{3.4}{\sqrt{102}} = 0.79

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 16 - 0.79 = 15.21 ounces

The upper end of the interval is the sample mean added to M. So it is 16 + 0.79 = 16.79 ounces

The 98 percent confidence interval for the population mean μ is between 15.21 ounces and 16.79 ounces.

4 0
2 years ago
0.327 rounded to the nearest hundredths
daser333 [38]
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3 years ago
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postnew [5]

Answer:

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You must divide how far the anchor must go (27.5 ft) by the speed it travels (0.07 feet per second). 27.5 / 0.07 = 250 seconds.

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