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ELEN [110]
3 years ago
11

BRAINLIEST ASAP! PLEASE HELP ME :)

Mathematics
1 answer:
enot [183]3 years ago
3 0

Answer:

second option

Step-by-step explanation:

A side is given, since both triangles have a same side, the criss cross shows that the angles are also the same

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Selena bought a shirt on sale that was 20% less than the original price. the original price was five dollars more than the sale
8090 [49]
20%+5=x x=original price
5 0
3 years ago
The GCF of 12 and 15 is _____.
sladkih [1.3K]

Answer:

3.

Step-by-step explanation:

To find the GCF of two numbers:

List the prime factors of each number.

Multiply those factors both numbers have in common. If there are no common prime factors, the GCF is 1.



Hope This Helps!

If you have anymore questions, Just ask me!

Mark Brainliest If anyone Else Answers Please to help me get to the next Rank!

#RoadToVituoso!

                     - Innverted



4 0
3 years ago
Read 2 more answers
Simplify -5(4y-7x)+8(3x-2y)
guajiro [1.7K]

Answer:59x-36y

Step-by-step explanation:

-5(4y-7x)+8(3x-2y)

Open the brackets

-20y+35x+24x-16y

Collect like terms

-20y-16y+35x+24x

-36y+59x

Rearrange we get

59x-36y

5 0
3 years ago
All of the questions in the picture
schepotkina [342]

(1) Recall the angle sum identity for cosine:

cos(<em>x</em> + <em>y</em>) = cos(<em>x</em>) cos(<em>y</em>) - sin(<em>x</em>) sin(<em>y</em>)

So

cos(<em>π</em>/3) cos(5<em>π</em>/6) - sin(<em>π</em>/3) sin(5<em>π</em>/6) = cos(<em>π</em>/3 + 5<em>π</em>/6)

= cos(7<em>π</em>/6)

= -√(3)/2

(2) Recall the half-angle identity:

cos²(<em>x</em>) = (1 + cos(2<em>x</em>))/2

Since <em>π</em>/2 < 7<em>π</em>/12 < <em>π</em>, you should expect cos(7<em>π</em>/12) < 0. So solving for cos(<em>x</em>) above, we have

cos(<em>x</em>) = -√[(1 + cos(2<em>x</em>))/2]

Then

cos(7<em>π</em>/12) = -√[(1 + cos(7<em>π</em>/6))/2]

= -√[(1 - √(3)/2)/2]

= -√[1/2 - √(3)/4]

You could stop there, or continue and try to de-nest the radicals to end up with

= (√(2) - √(6))/4

(3) Recall the angle sum formula for tangent:

tan(<em>x</em> - <em>y</em>) = (tan(<em>x</em>) - tan(<em>y</em>))/(1 + tan(<em>x</em>) tan(<em>y</em>))

Then

(tan(122°) - tan(32°))/(1 + tan(122°) tan(32°)) = tan(122° - 32°)

= tan(90°)

which is undefined, since tan(<em>x</em>) = sin(<em>x</em>)/cos(<em>x</em>), and cos(90°) = 0.

(4) Recall the double angle identity for sine:

sin(2<em>x</em>) = 2 sin(<em>x</em>) cos(<em>x</em>)

Then

2 sin(15°) cos(15°) = sin(30°)

= 1/2

(5) Use the double angle identity for cosine:

cos(2<em>x</em>) = 2 cos²(<em>x</em>) - 1

Then

12 cos²(<em>θ</em>) - 6 = 6 (2 cos²(<em>θ</em>) - 1)

= 6 cos(2<em>θ</em>)

(6) Use the sine double angle identity mentioned in (4):

7 cos(4<em>x</em>) sin(4<em>x</em>) = 7/2 (2 cos(4<em>x</em>) sin(4<em>x</em>))

= 7/2 sin(8<em>x</em>)

Consult the other question you commented on [19739123 in the URL] for details on (7) and (8).

3 0
3 years ago
Tion of your knowledge on the nature of roots:
MAXImum [283]

Answer:

The roots are not real.

Step-by-step explanation:

To prove : The roots of  I/2 +9 (1-k) are real for all real values of k ?Solution :

The roots are real when discriminant is greater than equal to zero.

i.e b2-4ac>0 But the roots are imaginary therefore the roots of the given equation are not real for any value of k.If x²+kx+k=0, find the value of k, If the roots are real & equal.​

3 0
3 years ago
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