Answer:
D) 5,200
Step-by-step explanation:
The formula to find the area of a r rectangle: l x w, where l is the length and w is width.
Area of the backyard: 50 x 80
= 4,000 ft
Area of the house: 40 x 30
= 1,200 ft
Total = 4,000 + 1,200
= 5,200 ft²
Answer: A. Use Pythagorean Theorem to prove that KL is equal to c.
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Explanation:
If we could show that KL = c, then we can tie together the following pairs of segments
- EG = KM = a
- GF = ML = b
- EF = KL = c
Then we'd use the SSS congruence theorem to prove the triangles are congruent. The last step is to use CPCTC to conclude that angle EGF is a 90 degree angle.
Keep in mind that we need to know the actual numeric values of 'a' and 'b' to be able to determine the value for c. So without the numbers, the Pythagorean theorem isn't really useful; however, I can see where your teacher is going with this line of logic. Your teacher is effectively just laying out a basic outline more or less.
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Notes:
- SSS = side side side
- CPCTC = corresponding parts of congruent triangles are congruent
Answer:
The sum of the coefficients of the terms in (-1.5·x² + 0.5·x + 4)¹⁶ that have even degree is -4273411167.501
Step-by-step explanation:
The parameters given are;
f(-4) = -22
f(-1) = 2
f(2) = -1
g(x) = f(x)¹⁶
The function f(x) is presented as follows;
f(x) = a·x² + b·x +c
We have;
-22 = a·(-4)² + b·(-4) +c
-22 = a·16 - 4·b +c ..............(1)
2 = a·(-1)² + b·(-1) +c
2 = a - b +c...........................(2)
-1 = a·(2)² + b·(2) +c
-1 = 4·a + 2·b +c...................(3)
Solving the equations (1), (2), and (3) by using an online linear systems solver, we get;
a = -1.5, b = 0.5, c = 4
Therefore, f(x) = -1.5·x² + 0.5·x + 4
f(x)¹⁶ = (-1.5·x² + 0.5·x + 4)¹⁶ which gives the coefficients of the even terms as follows;
656.841 - 19267.331 + 248302.054 - 1772904.419 + 6735603.932 - 2868054.635 - 119602865.901 + 750783340.827 + -2542435585.611 + 5338903756.992 - 6048065910.25 -1031335136 + 17223697920 - 32238338048 + 32107397120 - 17716740096 = -4273411167.501.
Answer:
40
Step-by-step explanation:
count the blocks
