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Gennadij [26K]
3 years ago
7

You speak to a business owner that is taking in almost $2,000 in revenue each month. The owner still says that they’re having tr

ouble keeping the doors open. How can that be possible? Use the terms revenue, expenses, and profit/loss in your answer.
Computers and Technology
1 answer:
Serga [27]3 years ago
7 0
Let's say for example that the business is taking in $2000 of revenue.  That is the amount that the business collected for it's services - like for fixing the computer.  What if though it costs $500 for the equipment (that's an expense).  Now they only made $1500.  Now the customer complains and says that the computer isn't fixed properly so the company sends out a techie for 2 additional hours.  They need to pay their employee (another expense).  Now the $1500 is down to $1400.  They would have utilities to keep their lights on and insurance and many other expenses.

Your profit looks like this:
Profit = Revenue - Expenses
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Answer:

A strong resume must be short and complete.

Explanation:

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3 years ago
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Creating a Numpy Array
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2 years ago
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Korolek [52]

Answer:

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2 years ago
Write a program that asks the user to enter a number of seconds. There are 60 seconds in a minute. If the number of seconds ente
frez [133]

Answer:

// here is code in c.

#include <stdio.h>

// main function

int main()

{

// variable to store seconds

long long int second;

printf("enter seconds:");

// read the seconds

scanf("%lld",&second);

// if seconds is in between 60 and 3600

if(second>=60&& second<3600)

{

// find the minutes

int min=second/60;

printf("there are %d minutes in %lld seconds.",min,second);

}

// if seconds is in between 3600 and 86400

else if(second>=3600&&second<86400)

{

// find the hours

int hours=second/3600;

printf("there are %d minutes in %lld seconds.",hours,second);

}

// if seconds is greater than 86400

else if(second>86400)

{

// find the days

int days=second/86400;

printf("there are %d minutes in %lld seconds.",days,second);

}

return 0;

}

Explanation:

Read the seconds from user.If the seconds is in between 60 and 3600 then find the minutes by dividing seconds with 60 and print it.If seconds if in between 3600 and 86400 then find the hours by dividing second with 3600 and print it. If the seconds is greater than 86400 then find the days by dividing it with 86400 and print it.

Output:

enter seconds:89

there are 1 minutes in 89 seconds.

enter seconds:890000

there are 10 days in 890000 seconds.

8 0
2 years ago
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