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Gennadij [26K]
4 years ago
7

You speak to a business owner that is taking in almost $2,000 in revenue each month. The owner still says that they’re having tr

ouble keeping the doors open. How can that be possible? Use the terms revenue, expenses, and profit/loss in your answer.
Computers and Technology
1 answer:
Serga [27]4 years ago
7 0
Let's say for example that the business is taking in $2000 of revenue.  That is the amount that the business collected for it's services - like for fixing the computer.  What if though it costs $500 for the equipment (that's an expense).  Now they only made $1500.  Now the customer complains and says that the computer isn't fixed properly so the company sends out a techie for 2 additional hours.  They need to pay their employee (another expense).  Now the $1500 is down to $1400.  They would have utilities to keep their lights on and insurance and many other expenses.

Your profit looks like this:
Profit = Revenue - Expenses
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Write the following functions. Each function needs function comments that describes function and its parameters double sphereVol
luda_lava [24]

Answer:

Output

height: 10

radius: 2

Cylinder volume: 125.6

Cone Surface: 76.6037

Cone Volume: 41.8667

Sphere volume: 33.4933

Sphere surface: 50.24

Cylinder volume: 125.6

Explanation:

//Declaring variables

#include <iostream>

#include <cmath>

using namespace std;

//Defining Pi value

const double PI=3.14;

//Decliring the functions

//volume function for cone

double volumeCone(double r,double h){

       return  PI * r * r  * (h/3);

}

//volume function for sphere surface

double surfaceSphere(double r){

       return 4 * PI  * r * r;

}

//volume function for cylinderVol

double cylinderVol(double r,double h){

       return  PI * r * r * h;

}

//volume function for sphere volume

double sphereVol(double r){

       return 4/3.0 * PI * r * r * r;

}

//volume function for cone surface

double surfaceCone(double r,double h){

       return  PI * r * (r+sqrt(h *h + r  * r));

}

int main(){

       double r,h;

//print the values of height and radius

       cout<<"height: ";

       cin>>h;

       cout<<"radius: ";

       cin>>r;

//print the values of geometric forms

       cout<<"Cylinder volume: "<<cylinderVol(r,h)<<endl;

       cout<<"Cone Surface: "<<surfaceCone(r,h)<<endl;

       cout<<"Cone Volume: "<<volumeCone(r,h)<<endl;

       cout<<"Sphere volume: "<<sphereVol(r)<<endl;

       cout<<"Sphere surface: "<<surfaceSphere(r)<<endl;

       cout<<"Cylinder volume: "<<cylinderVol(r,h)<<endl;

       

       

}

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Answer:

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